Question

Solve 3x2 + x + 10 = 0. Round solutions to the nearest hundredth.

Answer 1

$3 x^{2} + x + 10 = 0$
$x = \frac{-b(+or-) \sqrt{ b^{2} - 4ac } }{2a}$
$x = \frac{-1(+or-) \sqrt{ 1^{2} - 4(3)(10) } }{2(3)}$
: . x =  \frac{-1 +  \sqrt{-119} }{6}   OR   $x = \frac{-1 - \sqrt{-119} }{6}$

Thus the roots or the solutions to this equation are imaginary because the discriminant $\sqrt{-119}$ is negative and a negative number is undefined when rooted.