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Eduardwww [97]
3 years ago
6

3(y-10)+1=x(y-8) HELP I NEED TO SHOW WORK IVE ALREADY POSTED THIS 2 TIMES

Mathematics
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

try make one tutor help u that what I do to understand better.they go step but step

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What number divided by 2 3 4 5 6 has a remainder of 1 but when divided by 7 has no remainder?
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We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...

However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.

Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7). 

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