The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Just finished doing the math and the correct answer should be B: 5.3 Hope this helps:)
6.5X + 9(30) = 8(30+X)6.5X +270 = 240 + 8X270-240 = 8X-6.5X1.5X = 30X = 30/1.5 =20 ounces of $6.50 alloy9 is within 1 of 86.5 is within 1.5 of 81.5 is 3/2 of 130 is 3/2 of 20You know you need more of $9 alloy since it's closer to $8You need exactly 3/2 or 1.5 times more of the $9 alloy30 is 1.5 times 20
Answer:
I = V/R
Step-by-step explanation:
V = IR
Divide by R on both the sides,
I = V/R
Answer:
13/48
Step-by-step explanation:
I take the middle sign to be plus.\
3/4//4/5 = 3/4 * 5/4 = 15/16
15/16 - 2/3 =
The lowest common denominator would be 48: 16 and 3 are prime to each other.
45/48 - 32/48 = 13 / 48
Where did the minus come from? I take it that there is a minus sign in front of the 2