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Oksanka [162]
3 years ago
6

What number pattern is generated by the following

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0

Answer:

nth term = 1 + n(13/4)

Step-by-step explanation:

3n + n/4 + 1

n = 1, 3(1) + (1)/4 + 1 = 4 + ¼ = 17/4

n = 2, 3(2) + (2)/4 + 1 = 7 + ½ = 30/4

n = 3, 3(3) + (3)/4 + 1 = 10 + ¾ = 43/4

n = 4, 3(4) + (4)/4 + 1 = 14 = 56/4

The difference between consecutive terms is 13/4

At n = 1, 17/4 = 1 + 1(13/4)

At n = 2, 30/4 = 1 + 2(13/4)

nth term = 1 + n(13/4)

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\frac{1}{5}x -  \frac{2}{3} y = 30  \\

Putting the value of Y = 15

\frac{1}{5} x -  \frac{2}{3}  \times 15 = 30  \\   \frac{1}{5} x = 30  +  10 \\  \frac{1}{5} x = 40 \\ x = 5 \times 40 \\  x = 200

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Here is your equation:

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Answer:

The answer is A.

Step-by-step explanation:

Firstly, you have to take out the common terms for this expression. In this expression, the common terms ard 2 and m :

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Next you have to factorise the brackets :

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So the final answer is :

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