Answer:

Step-by-step explanation:
The equation of line in the form .
y = mx + c
Where m is the slope and c is the y- intercept .
As given
The lines y=3x-1 and y=ax+2 are perpendicular .
Here 3 is slope for equation of line y=3x-1 and a is slope for equation of line
y=ax+2 .
Now by using properties of the perpendicular lines property .
When two lines are perpendicular than slope of one line is negative reciprocal of the other line .
Thus

Therefore 
The first one is -5,-3 ab.
A and c are true ! I hope this helps
Answer: (A)
Explanation: For there to be a solution at any one point, both inequalities must share a common point. This point will then satisfy both inequations, becoming a solution to both inequality.
Let's pick (A).
For there to be at least one solution, the first inequality must have a solution of

. Since the left side has clearly no points common to both graphs. Hence, no solution can exist that will satisfy both.
All of the other graphs have at least one point in common.
(B) has

(C) has

(D) has
Three plus three equals six :)