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3 years ago

What is the value of C in the equation 12c - 53 = 91?

Mathematics

1 answer:

kirza4 [7]3 years ago

3 0

Answer: 12

Step-by-step explanation:

C=12 because u do 91+53 =144 then 144/12=12

C=12

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3 years ago

Complete the square <br> x^2+4-12=0

Tatiana [17]

Answer:

x = -6

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Step-by-step explanation:

x² + 4 - 12 = 0

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3 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

3 years ago

Please Help, I can't figure out this problem

Otrada [13]

Answer:

<h2>The answer is 5 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question

The points are (9,-7) and (5, -4)

The distance between them is

$d = \sqrt{ ({9 - 5})^{2} + ({ - 7 + 4})^{2} } \\ = \sqrt{ {4}^{2} + ({ - 3})^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25}$

We have the final answer as

<h3>5 units</h3>

Hope this helps you

3 0

3 years ago

What is the value of C in the equation 12c - 53 = 91?￼

What is the value of C in the equation 12c - 53 = 91?