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solmaris [256]
2 years ago
12

Hillsdale's zoo has two elephants. The male elephant weighs 9 7/12 tons and the female elephant weighs 3 5/6 tons. How much more

does the male weigh than the female?
Mathematics
2 answers:
Alex Ar [27]2 years ago
7 0

Answer:

6 10/12

Step-by-step explanation:

thank u

serious [3.7K]2 years ago
5 0

Answer:

jdjdjdjjdjdjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

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Photo attached!!!!!!!
eimsori [14]

Answer:

i cant see the photo

Step-by-step explanation:

6 0
2 years ago
The two non-parallel sides of an isosceles trapezoid are each 7 feet long. The longer of the two bases measures 22 feet long. Th
Orlov [11]

The length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

<h3>How to determine the length</h3>

The cosine rule is given as;

c = \sqrt{a^2 + b^2 - 2ab cos \alpha }

c = length of the diagonal

a = base length = 22 feet

b = 7 feet

c = \sqrt{7^2 + 22^2 - 2 * 7 * 22 cos 40}

c = \sqrt{533 - 308 * 0. 7660}

c = \sqrt{533 - 235. 93}

c = \sqrt{297. 072}

c = 17. 24 feet

Using sine rule

\frac{a}{sin A }  = \frac{c}{sin C}

\frac{a}{sin 70}  = \frac{17. 24}{sin 40}

Cross multiply

a × sin 60 = c × sin 70

a × 0. 8660 = 17. 24 × 0. 9397

a = \frac{16. 20}{0. 8660}

a = 18. 7 feet long

Thus, the length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

Learn more about  isosceles trapezoid here:

brainly.com/question/10187910

#SPJ1

5 0
2 years ago
Which is the correct algebraic expression for the phrase, 14 more pickles than the first jar?
KIM [24]

Answer:A

Step-by-step explanation:

6 0
3 years ago
PLS HELP TEST ILL GIVE BRAINLIEST
topjm [15]

Answer:

Answer attached

Step-by-step explanation:

With reference to my figure

Shape 1 = square

Shape 2 = rectangle

5 0
3 years ago
If x=5 and y=2<br> ...........................
azamat

{ \bold{ - 5}}

{ \red{ \tt{given \: {\to}}}} \: { \bold{x = 5}} \:  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  { \bold{y = 2}}

{ \green{ \tt{ \sqrt{10y + x} - xy}}}

{ \green{ \tt{ \sqrt{10(2) + 5 }  - 5(2)}}}

{ \green{ \tt{ \sqrt{20 + 5}  - 10}}}

{ \green{ \tt{ \sqrt{25}  - 10}}}

{ \green{ \tt{5} - 10}}

=  { \bold{ - 5}}

8 0
9 months ago
Read 2 more answers
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