3 years ago

the sum of the measures of two interior angles of a triangle is 593°. Find the measure of the sixth interior angle

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

5 0

The sixth angle would measure 127°

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Find the area of the shaded region in square units. Show your reasoning.

motikmotik

Answer:

40 square units

Step-by-step explanation:

First of all, lets say that square has side $l$ , so, the area unit is $l^2$

the diagonal's square is $l\sqrt{2}$

CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)

$A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2$

CALCULATION OF MAIN SQUARE AREA

$A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2$

TOTAL AREA

$A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2$

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Answer:

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I have to estimate 9,105-4031 and im soo confused! Help me plss

balandron [24]

9105-4031= 5074

Step-by-step explanation:

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3[5x - 4] - [-30 - 45x]

Nimfa-mama [501]

$3(5x - 4) - (-30-45x)$
$= 15x - 12 + 30 + 45x$ <- Distributive Property
$=60x + 18$ <- Combine Like Terms

If you're trying to solve for 0:

$0 = 60 x + 18$
$-18 = 60x$ <- Subtracted 18 from both sides
$x = \frac{-18}{60} = \frac{-9}{30}$ <- Divided both sides by 60 and then simplified.

$x = \frac{-9}{30}$ <- Fraction Form
$x = -0.3$ <- Decimal Form

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Wewaii [24]

Answer:

LB=7701 3

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