Answer:
39.17% probability that a woman in her 60s who has a positive test actually has breast cancer
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Positive test.
Event B: Having breast cancer.
3.65% of women in their 60s get breast cancer
This means that 
A mammogram can typically identify correctly 85% of cancer cases
This means that 
Probability of a positive test.
85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So

What is the probability that a woman in her 60s who has a positive test actually has breast cancer?

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer
Answer:
Taybrownies1359Step-by-step explanation:
np
Answer:

Explanation:
The equation is:

and

<u>1. Subsittute n = 6 into the equation:</u>

Now subsititute the known values:

You can solve for 

<u />
<u>2. Substitute n = 5 into the equation:</u>

Substitute the known values and solve for 

<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u>
<u />


Avg. speed Joanna runs: 7.5km/h
how much she runs everyday: 15km
15km/7.5= 2 hours of running time everyday
She leaves at 8:30, comes back at ?
8:30+ 2:00= 10:30
Joanna arrives back at 10:30a.m.
Keeping in mind that 29/6 is greater than 4, is actually 4 and 5/6, so the amount we'll "add" will be a negative one.