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Cloud [144]
3 years ago
13

Please help it's due today. 62. Use a geometric formula to solve the problem. A square has an area of 81 meters. Find the side l

ength. I know the answer but I don't know what a geometric formula is.
Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0

Answer:

20.25

Step-by-step explanation:

81 divided by 4 sides = 20.25

frosja888 [35]3 years ago
3 0
A geometric formula is just a fancy way of saying formula or how you got you answer so to get the answer it’s 81 divided by 4 which gives you 20.25

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olganol [36]

Answer :

Points at (1, 3) and (3, 3) and (2, 1)

Explanation:

The original graph (dashed) is an absolute value function meaning f(x) = |x|

<u>Given:</u> y = 2f(x - 2) + 1

f(x - 2) means you plug in x - 2 for x in f(x) function

the new graph equation is: y = 2|x - 2| + 1

  • The graph will shift up 1 because +1
  • The graph will shift right because -2
  • The graph has a scale factor of 2
  • The graph is V shaped because it is an absolute value graph

Learn more about Absolute Value here: brainly.com/question/729268

<u>Visual:</u>

8 0
2 years ago
Can you solve what is 5 x 1 2/3
enot [183]
I believe the answer is 20 sorry
7 0
3 years ago
Read 2 more answers
What are the coordinates of X?
Darina [25.2K]

Answer:

Step-by-step explanation:

x is at (0, 4)

4 0
2 years ago
0.376×800=(0.376×_____)×100 =______×100 =______
sergey [27]
0.376*800

=(0.376*8)*100

=3.008*100

=300.8
3 0
3 years ago
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
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