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3 years ago

How would the domain & range of Y= 1/4x-6 be determined HELP ASAPP!!!

Mathematics

1 answer:

liq [111]3 years ago

5 0

Answer:

$Domain=\mathbb{R}\to x\in(-\infty,\ \infty)\\\\Range=\mathbb{R}\to x\in(-\infty,\ \infty)$

Step-by-step explanation:

$y=\dfrac{1}{4}x-6}$

It's an equation of a linear function in the slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

The domain of any linear function is the set of all real numbers.

The range of any linear function where m ≠ 0 is the set of all real number.

If m = 0, then the equation of a line is y = b. Then the range is {b}.

We have m = 1/4 ≠ 0. Therefore the range is the set of any real numbers.

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Which of the following statements is not true?

Verizon [17]

Whole numbers are the set of integers ranging from 0 - infinity. Natural numbers are the set of integers ranging from 1 - infinity. 0 is not a natural number but it is a whole number, so the second statement is false.

4 0

3 years ago

Read 2 more answers

Kamille brought a new outfit that cost $32.00. The tax rate is 9%. How much did she pay for the outfit after tax?

anastassius [24]

Answer:

Kamille paid $34.88 for her outfit after tax.

Ms. Roth will pay $59.16 in total.

Step-by-step explanation:

Kamille brought a new outfit that cost $32.00. The tax rate is 9%. How much did she pay for the outfit after tax?

32.00 x 0.09 = 2.88

32 + 2.88 = 34.88

Ms. Roth went to I-Hop for breakfast. She ordered pancakes for $5.00, eggs for $3.50, and orange juice for 42.50. if she tips the waiter 16%, how much will she pay in total?

5 + 3.5 + 42.50 = 51

51 x 0.16 = 8.16

51 + 8.16 = 59.16

6 0

3 years ago

The number of errors in a textbook follow a poisson distribution with a mean of 0.01 errors per page. what is the probability th

neonofarm [45]

Mean number of errors in each page = 0.01
Mean number of errors in 100 pages = 0.01*100=1

It is possible to use the cumulative distribution function (CMF), but the math is a little more complex, involving the gamma-function. Tables and software are available for that purpose.

Thus it is easier to evaluate with a calculator for the individual cases of k=0,1,2 and 3.

The Poisson distribution has a PMF (probability mass function)

$P(k):=\frac{\lambda^ke^{-\lambda}}{k!}$
with λ = 1
=>
$P(0):=\frac{1^0e^{-1}}{0!}=0.3678794$
$P(1):=\frac{1^1e^{-1}}{1!}=0.3678794$
$P(2):=\frac{1^2e^{-1}}{2!}=0.1839397$
$P(3):=\frac{1^3e^{-1}}{3!}=0.0613132$
=>
$P(k$
or
P(k<=3)=0.9810 (to four decimal places)

3 0

3 years ago

What is the solution to this equation? 4x^2+98=0

Bess [88]

There is no real solution