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Sliva [168]
3 years ago
5

The width of the fountain in Luke's drawing from the example is 2 cm. What is the width of the fountain in Isabella's scale draw

ing?

Mathematics
2 answers:
Firdavs [7]3 years ago
8 0
2.5cm


I Did the quiz
Setler79 [48]3 years ago
5 0

Answer:

2.5cm

Step-by-step explanation:

If Luke's scale for his drawing is 5m to 2cm, then it means that every 2cm on Luke's scale drawing represents 5m in real life. So since the width of the fountain is 2cm, the actual fountain width must be 5m. As established in the example, Isabella's scale factor from drawing to real life is 6/3=2, which means any measurement in cm on her drawing can simply be multiplied by 2 to obtain the real life measurement in m. So, to convert back the other way, from real-life to drawing, we just need to divide the value by 2 instead of multiply. So, if the real life value is 5m, then the width on her scale drawing should be 5/2 = 2.5cm.

Hope this helped!

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Write an equation for each line. m=-5 and the y -intercept is (0,-7) .
Veronika [31]

The equation of the line for given values is y = -5x - 7.

<h3>Given a point and a slope, how do you build an equation for a line?</h3>

When you know the slope of the line to be investigated and the provided point is also the y intercept, you may utilize the slope intercept formula, y = mx + b. (0, b). The y value of the y intercept point is denoted by the symbol b in the formula.

The standard equation of straight line is y = mx + c.

Given m = -5 and y - intercept is -7

So, the equation of the line becomes y = -5x - 7

To learn more about equation of the line from given link

brainly.com/question/18831322

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6 0
1 year ago
If a is a rational number and B is an irrational number can the product of a and b be rational
MAXImum [283]

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3 years ago
Question 5(Multiple Choice Worth 1 points)
Snezhnost [94]

Given:

The graph passes through the points (0,-20) and (4,10).

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The equation of line that most closely represents the line depicted in the graph.

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If a line passing through two points, then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The given line passes through the points (0,-20) and (4,10). So, the equation of line is

y-(-20)=\dfrac{10-(-20)}{4-0}(x-0)

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f(x)=\dfrac{15}{2}x-20

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7 0
3 years ago
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