Answer:
The cost of producing the article is -3500 (Negative cost)
Step-by-step explanation:
The given parameters are
The ratio of the profit to material cost to production labor = 5:7:13
The amount of the material cost = 840 + Labor cost
Let the total cost = X
Therefore, we have;
The fraction of the total cost that is material cost = 7/(5 + 7 + 13) = 7/25
Therefore, the material cost = 7/25 × X
The fraction of the total cost that is labor cost = 13/(5 + 7 + 13) = 13/25
Therefore, the labor cost = 13/25 × X
However, the amount of the material cost = 840 + Labor cost, which gives;
7/25 × X = 13/25 × X + 840
7/25 × X - 13/25 × X = 840
-6/25 × X= 840
X = 840/(-6/25) = 840×(-25/6) = -3500
The cost of producing the article = -3500.
Answer:
A, B, D, F
Step-by-step explanation:
Matrix operations require that the matrix dimensions make sense for the operation being performed.
Matrix multiplication forms the dot product of a row in the left matrix and a column in the right matrix. That can only happen if those vectors have the same dimension. That is the number of columns in the left matrix must equal the number of rows in the right matrix.
Matrix addition or subtraction operates on corresponding terms, so the matrices must have the same dimension.
The transpose operation interchanges rows and columns, so reverses the dimension numbers. It is a defined operation for any size matrix.
<h3>Defined operations</h3>
A. CA ⇒ (4×7) × (7×2) . . . . defined
B. B -A ⇒ (7×2) -(7×2) . . . . defined
C. B -C ⇒ (7×2) -(4×7) . . . undefined
D. AB' ⇒ (7×2) × (2×7) . . . . defined
E. AC ⇒ (7×2) × (4×7) . . . undefined
F. C' ⇒ (7×4) . . . . defined
The radius is 22 for this , good luck my friend!!
Answer:
18) Area= 5*5/2=25/2=12.5 unit ^2
19) Area=AB^2V3/4=8a^2*V3/4=2V3a^2
Step-by-step explanation:
18. A(-3,0)
B(1,-3)
C(4,1)
AB=V(-3-1)^2+(0+3)^2=V16+9=V25=5
AC=V(-3-4)^2+(0-1)^2=V49+1=V50=5V2
BC=V(1-4)^2+(-3-1)^2=V9+16=V25=5
so AB=BC=5
and AC^2=AB^2+BC^2
so trg ABC is an isosceles right angle triangle (<B=90)
Area= 5*5/2=25/2=12.5 unit ^2
19. A(a,a)
B(-a,-a)
C(-V3a, V3a)
AB=V(a+a)^2+(a+a)^2=V4a^2+4a^2=V8a^2
AC=V(a+V3a)^2+(a-V3)^2=Va^2+2a^2V3+3a^2+a^2-2a^2V3+3a^2=V8a^2
BC=V(-a+V3a)^2+(-a-V3a)^2=V8a^2
so AB=AC=BC
Area=AB^2V3/4=8a^2*V3/4=2V3a^2
