Question

The length of a rectangle is 5cm more than its breadth . if the perimeter of the rectangle is 40cm , find the dimension of the rectangle .
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Answer 1

• Breadth be x
• Length be x+5

ATQ

$\\ \sf\longmapsto 2(x+x+5)=40$

$\\ \sf\longmapsto 2(2x+5)=40$

$\\ \sf\longmapsto 2x+5=20$

$\\ \sf\longmapsto 2x=15$

$\\ \sf\longmapsto x=7.5$

• Length=12.5cm
• Breadth=7.5cm

Answer 2

• Let the breadth of the rectangle be x cm
• lenght of the rectangle = ( x + 5 ) cm

perimeter of the rectangle = 2 ( l + b )

• 2 ( x + x + 5 ) cm
• 2 ( 2x + 5') cm
• ( 4x + 10 ) cm

4x + 10 = 40

4x = 40 10 ( transpose 10 to RHS )

x = 30/4 = 7.5 ( divide both sides by 4 )

• lenght of the rectangle = x + 5 = 7.5 + 5 = 12.5 cm
• breadth of the rectangle = x = 7.5 cm