1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anygoal [31]
3 years ago
12

How many moles are in 3.57 x 10 32 particles Ca?

Chemistry
1 answer:
valentina_108 [34]3 years ago
8 0

Answer:

\boxed {\boxed {\sf 592,826,303.6 \ moles \ of \ Ca }}

Explanation:

To convert from moles to particles, we must Avogadro's Number.

6.022*10^{23}

This number tells us the number of particles (atoms, ions, molecules, etc.) in 1 mole of a substance. In this case, it is the particles of calcium in 1 mole of calcium.

6.022*10^{23} \ particles \ Ca / mole \ Ca

We can use Avogadro's Number as a ratio or fraction.

\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}

Multiply this by the given number of particles (3.57*10³²).

3.57*10^{32} \ particles \ Ca*\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}

Flip the fraction so the particles of calcium will cancel out.

3.57*10^{32} \ particles \ Ca*\frac{1 \ mol \ Ca}{6.022 *10^{23} \ particles \ Ca}

3.57*10^{32} *\frac{1 \ mol \ Ca}{6.022 *10^{23} }

\frac{3.57*10^{32} \ mol \ Ca}{6.022 *10^{23} }

592826303.6 \ mol \ Ca

There are <u>592,826,303.6 moles</u> of calcium in 3.57*10³² particles of calcium.

You might be interested in
36. What is the pH of a solution with an H3O+ concentration of 5.67 x104 M?
skad [1K]
The answer for your question is B
4 0
3 years ago
Which area of science is considered the central science?
denis-greek [22]
Chemistry is the area considered the central science
7 0
3 years ago
Read 2 more answers
1. What is the mass of a rock that has a density of 2.5 grams per cubic centimeter and a volume of 4.0
dangina [55]

Answer:

Explanation:

d =

m

V

m = d×V

V =

m

d

DENSITY

Density is defined as mass per unit volume.

d =

m

V

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =

m

V

=

433

g

200

c

m

³

= 2.16 g/cm³

MASS

d =

m

V

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×

1.11

g

1

m

L

= 555 g

VOLUME

d =

m

V

We can rearrange this to get the expression for the volume.

V =

m

d

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×

1000

g

1

k

g

= 14 830 g

Step 2: Calculate the volume.

V =

m

d

= 14 830 g ×

1

c

m

³

19.32

g

= 767.6 cm³

7 0
4 years ago
an atmosphere is considered hazardous if it contains a hazardous gas in excess of 10 percent of the hazardous material's:
svlad2 [7]

Lower flammable limit means the lowest concentration of a material that will propagate a flame.

What is hazardous atmosphere?

It is an atmosphere that may expose employees to risk of death, incapacitation, impairment of ability to self-rescue, injury, or acute illness from one or more of following causes

  • Flammable gas, vapor, or mist in excess of 10 percent of lower flammable limit (LFL)
  • Airborne combustible dust at concentration that meets or exceeds its LFL

What is lower flammable limit?

  • It means the lowest concentration of a material that will propagate a flame.
  • The LFL is usually expressed as percent by volume of material in air (or other oxidant)
  • Atmospheres with concentration of flammable vapors at or above 10 percent of lower explosive limit (LEL) are considered hazardous when located in confined spaces.
  • However, atmospheres with flammable vapors below 10 percent of LEL are not necessarily safe. Such atmospheres are too lean to burn

Learn more about lower flammable limit at brainly.com/question/2456135

#SPJ4

6 0
1 year ago
What is the molality of a solution composed of 342 moles of sugar (C12H22O11) dissolved in 171 kilograms of water (H20)?
4vir4ik [10]
Molality=mol/kg

342/171

=2m

Hope this helped :)
5 0
2 years ago
Other questions:
  • Consider a balloon that has a volume V. It contains n moles of gas, it has an internal pressure of P, and its temperature is T.
    13·2 answers
  • Drag the description to the category
    11·1 answer
  • Which of the following elements will gain electrons to form an
    8·1 answer
  • What type of intermolecular forces are present in liquid methanol?
    7·1 answer
  • 3. In what grade level do students grow the quickest?
    13·1 answer
  • By what process does water vapor become a cloud?
    11·2 answers
  • (NEED HELP ASAP)
    8·1 answer
  • Which objects are scratched?
    5·2 answers
  • The equilibrium constant kp at 427°c for the reaction n 2( g) 3h 2( g) 2nh 3( g) is 9. 4 × 10 –5. what is δ g° for the reaction
    6·1 answer
  • When placed inside of a magnetic field, nmr active nuclei act in what way? (1 pt)
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!