Answer:
1.) The balanced equation is 3MgO(s) + 2Fe(s) ===> Fe2O3(s) + 3Mg(s)
2.) 20g of Fe2O3 will be produced by 20 ×120/160 = 15g of MgO
Explanation:
THE CORRECT EQUATION IS: MgO(s) + ___ Fe(s) ===> Fe2O3(s) + ___ Mg(s)
The balanced equation is: 3MgO(s) + 2Fe(s) ===> Fe2O3(s) + 3Mg(s)
molar mass of 3MgO = 3(24 + 16) = 120
Molar mass of Fe2O3 = 2 X 56 + 3 X 16
=112 +48 =160
From the equation, 120g of MgO Produced 160g of Fe2O3
Therefore 20g of Fe2O3 will be produced by 20 ×120/160 = 15g of MgO.
