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Neko [114]
3 years ago
9

Does anyone get this? Like filling in the blanks

Mathematics
2 answers:
miv72 [106K]3 years ago
7 0

I wanna say number of unfavorable outcomes on the bottom. Not 100% about that one though. But I'm quite sure number of winners goes on the top of the second one.

Arada [10]3 years ago
5 0

Answer:

Number of Favorable Outcomes over Total Number

Step-by-step explanation:

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a rectangle has a width of 4 cm and a length of 8cm is scaled by a factor of 6.what are the side lengths of the scaled copy
vichka [17]

Answer:

\huge\boxed{\text{Width: } 24 \ \ \ \text{Length: } 32}

Step-by-step explanation:

When we scale an object by a scale factor, the side lengths become the scale factor times bigger than the previous sides. Therefore, with a scale factor of 6, the side lengths would be multiplied by 6.

4 \cdot 6 = 24\\\\4 \cdot 8 = 32

Hope this helped!

6 0
3 years ago
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The Big Dipper ice cream store charges 25 cents for a cone and 75 cents for each scoop of ice cream added to the cone. What will
yulyashka [42]
Double dip ice-cream cone = 25 + 2(75) = 175 cents = $1.75


Answer: $1.75
4 0
3 years ago
Read 2 more answers
How many pounds of $2.4/lb trail mix should a grocer combine with 5 lb of $1.5/lb trail mix to get $1.9/lb trail mix?
user100 [1]
4
1.5x5=7.5 + (2.4 x 4)
/9
=1.9
8 0
2 years ago
What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2​
tangare [24]

The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2

Expanding the expression, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)

Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

7 0
3 years ago
I have ten minutes to send it in.​
dsp73

Refer to the attachment for answer

3 0
3 years ago
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