Answer: 3
Step-by-step explanation:
By the intersecting chords theorem,
Please help me with my work
1 answer:
,so first split them into separate shapes (refer to pic) then calculate each one
I started with the triangle
8×6=48 and 48÷2=24 so the triangles area its 24
next the rectangle
12×8=96
and I did the triangle shape cut out of the square
4×3=12 12÷2=6 so its area is 6
and the squares area is 8×8=64
but u need to subtract 6 from 64 because that area is missing
then you get 64-6=58
then add all the areas
58+24+96 to get your answer of 178m
I started with the triangle
8×6=48 and 48÷2=24 so the triangles area its 24
next the rectangle
12×8=96
and I did the triangle shape cut out of the square
4×3=12 12÷2=6 so its area is 6
and the squares area is 8×8=64
but u need to subtract 6 from 64 because that area is missing
then you get 64-6=58
then add all the areas
58+24+96 to get your answer of 178m
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Answer:
Leg side along the wall = x ft = 8 ft
The other leg side = 7+x ft = 7+8=15 ft
The Hypotenuse =9+x ft = 9+8 = 17 ft
Step-by-step explanation:
In the question, the shape of the pool is right triangle.
Let the leg side along the wall to be the x ft
Let the other leg side to be 7+x ft
Let the longest side/hypotenuse to be x+9 ft
Apply the Pythagorean relationship where the sum of squares of the legs equals the square of the hypotenuse
This means;
Expand the terms in brackets
collect like terms
solve for x in the quadratic equation by factorization
Taking the positive value of x;
x=8ft
Finding the lengths
Leg side along the wall = x ft = 8 ft
The other leg side = 7+x ft = 7+8=15 ft
The Hypotenuse =9+x ft = 9+8 = 17 ft
Answer:
Step-by-step explanation:
The first equation is
The second equation is
When we graph these two equations, <em>they will meet at a point which represent the solution of the two equations</em>.
We can solve the two equations simultaneously to determine their point of intersection.
Let us substitute the second equation into the first equation to get;
Multiply through by 2 to get;
Group similar terms to obtain;
Simplify;
Divide both sides by 3;
Put into the second equation;
Therefore the graphs of the two functions intersect at (2,3)
See graph in attachment.
