Question

Andres eats 2/3 of a bag of chips today at lunch time.Tommorow he will eat 1/2 of the left over with lunch.How much of the whole bag of chips will he eat in total

Answer 1

Answer:

$\frac{5}{6}$ part of the whole bag of chips he will eat in total.

Step-by-step explanation:

Given:

Part of chips eaten today = 2/3

Part of chips to be eaten tomorrow = 1/2 of the left over.

Now, considering the whole part be 1.

So, part left over = $1-\frac{2}{3}=\frac{3-2}{3}=\frac{1}{3}$

Now, part of chips to be eaten tomorrow = $\frac{1}{2}\times \frac{1}{3}=\frac{1}{6}$

Now, total part eaten is the sum of parts eaten today and tomorrow. So,

Total part eaten = $\frac{2}{3}+\frac{1}{6}$

Adding by making the denominator same, we have

Total part eaten = $\frac{2\times 2}{3\times 2}+\frac{1}{6}$

Total part eaten = $\frac{4}{6}+\frac{1}{6}$

Total part eaten = $\frac{4+1}{6}=\frac{5}{6}$

Therefore, $\frac{5}{6}$ part of the whole bag of chips he will eat in total.