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levacccp [35]
4 years ago
5

A toxic radioactive substance with a density of 7 milligrams per square centimeter is detected in the ventilating ducts of a nuc

lear processing building that was used 45 years ago. If the half-life is 20 years, what was the density of the substance when it was deposited 45 years ago?
Mathematics
1 answer:
uysha [10]4 years ago
5 0
For this case we have an equation of the form:
 y = A * (b) ^ t
 Where,
 A: initial amount
 b: decrease rate
 t: time in years.
 Substituting values we have:
 7 = A * (0.5) ^ ((1/20) * t)
 For t = 45 years we have:
 7 = A * (0.5) ^ ((1/20) * 45) 
 Clearing A:
 A = 7 / ((0.5) ^ ((1/20) * 45))
 A = 33.3
 Answer:
 
the density of the substance when it was deposited 45 years ago was:
 
A = 33.3 milligrams per square centimeter
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The proportion who had<em> no such experience</em> was 0.362

<h3>
How the find the proportion?</h3>

Given:

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Find the vertex of y = x2 + 14x − 40 by completing the square. A. (−7, 89) B. (−89, −7) C. (7, 89) D. (−7, −89)
irga5000 [103]

Alright, lets get started.

y = x^2 + 14 x - 40

For making complete square, we will add and subtract 49 in this

y = x^2 + 14 x - 40 + 49 - 49

y = x^2 + 14 x + 49 -40 - 49

y = (x+7)^2 - 40 - 49

y = (x+7)^2 - 89

Comparing the standard equation of parabola

y = a (x-h)^2 + k where (h,k) are vertex

So, comparing the equation with standard one, h, k would be = (-7 , -89)

So, the vertex are (-7 , -89) : Answer

Hope it will help :)

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4 years ago
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