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kvasek [131]
3 years ago
6

A typical cell in an animal's body is considered

Biology
1 answer:
bekas [8.4K]3 years ago
7 0

The correct Answer is diploid, i just took the test..................

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Most peripheral nerves are _____, carrying both sensory & motor impulses.
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Most peripheral nerves are nerves outside the brain and the spinal cord, carrying both sensory and motor impulses. The peripheral nervous system is one of the two components of the nervous system, the other part is the central nervous system. Peripheral nerves are classified into motor, sensory and autonomic nerves. 
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Choose the hypothesis for this controlled experiment that answers this question: "Does sunlight cause dyes in clothing to fade?"
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I think the answer is A because direct sunlight causes dyes in clothes to fade quietly.
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you are a molecule of phosphorus. choose a starting point in the phosphorus cycle and describe the process you would go through
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Which of the following is not an effect of complement activation? Select one: Interference with viral replication Increased phag
Nostrana [21]

Answer:

The correct answer is "Interference with viral replication".

Explanation:

The complement system is an essential part of the immune system that involves the activation of a series of proteins that act as a cascade and result in the development of inflammatory responses that help to fight infections. There are multiple effects of complement activation, however interference with viral replication is not one of them. The molecules that are able to interfere with viral replication are called interferons, and they synthesis and activation are not related with complement activation.

6 0
4 years ago
A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
6 0
3 years ago
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