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RideAnS [48]
3 years ago
12

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type

Chemistry
2 answers:
slavikrds [6]3 years ago
8 0

Answer:

Hi! In this case, the reactioncan be correctly balance according to this: 2Al(s) + 3CuSO4(aq) –> Al2(SO4)3(aq) + 3Cu(s).

Explanation:

In this particulary reaction,two semi-reactions happens.

One involving the metallic aluminum that suffers an oxidation reaction:

Al (s) -> Al3 + (aq) + 3e–

and another is a reduction reaction involving copper;

2e– + Cu2 + (aq) -> Cu (s)

DIA [1.3K]3 years ago
5 0

Answer:

2Al(s) + 3CuSO4(aq). --------> Al2(SO4)3(aq) + 3Cu(s)

Explanation:

This is a displacement reaction. Aluminum, being higher in the electrochemical series (higher electrode potential) displaces copper from its aqueous salt to give an aluminum salt and copper metal.

The equation is balanced with the formula of the products in mind. Since the products must be Al2(SO4)3 and 3Cu, then the stoichiometric coefficient of aluminum must be 2 on the reactant side and that of CuSO4 must be 3 on the reactants side.

This fulfils the general principle for balancing reaction equations which states that, the number of atoms of each element on the right hand side of the reaction equation, must be the same as the number of atoms of the same element on the left hand side of the reaction equation.

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matrenka [14]

Answer:

234.35 °C

Explanation:

Given data:

Volume of balloon = 125000 mL

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Solution:

Formula:

PV = nRT

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n = number of moles

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Volume of balloon = 125000 mL × 1 L /1000 mL

Volume of balloon = 125 L

Now we will put the values:

Ideal gas constant = R = 0.0821 atm.L/mol.K

PV = nRT

T = PV/nR

T = 1 atm × 125 L/  0.0821 atm.L/mol.K × 3 mol

T= 125  /0.2463 /K

T = 507.5 K

K to °C

507.5 K - 273.15 = 234.35 °C

4 0
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Answer:
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