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timurjin [86]
3 years ago
5

How many grams are in 4.56 moles of Mg(OH)2

Chemistry
1 answer:
GalinKa [24]3 years ago
3 0
D. divide 4.56 by molar mass of mg(OH)2
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Which of the following is not Made up of atoms?<br> A.Dust<br> B.Golf Ball<br> C.Sound<br> D.The Sun
juin [17]
The correct answer is C - sound.
Sound is a wave, and it is thus not considered a form of matter.
7 0
4 years ago
If 4.80 mol Ca mixed with 2 mol N2, which is the limiting reactant? 3Ca (s) + N2 (g) Ca3N2 (s)
Andreyy89
Nitrogen in the limiting reactant x
4 0
2 years ago
The formation of nitric oxide (N2(g) + O2(g) Imported Asset 2NO(g)) has a Kc value of 4.7 × 10-31. A classmate claims that this
riadik2000 [5.3K]
Answer is: her reasoning is flawed, because <span>Kc is very small, so the concentration of nitric(II) oxide is also very small. </span>

Balanced chemical reaction: N₂(g) + O₂(g) ⇄<span> 2NO(g).
</span>The equilibrium constant<span> (Kc) is a ratio of the concentration of the products (in this reaction nitrogen(II) oxide) to the concentration of the reactants (in this reaction nitrogen and oxygen):
</span>Kc = [NO]² / [N₂] · [O₂].
Kc = 4.7·10⁻³¹.
If we take equilibrium concentration of oxygen and nitrogen to be 1 M:
[N₂] = [O₂] = 1 M.
[NO] = √[N₂] · [O₂] · Kc.
[NO] = 6.855·10⁻¹⁶ M; equilibrium concentration of nitric oxide.
5 0
4 years ago
A chemistry student needs of acetic acid for an experiment. He has available of a w/w solution of acetic acid in acetone. Calcul
Volgvan

Answer:

49.4 g Solution

Explanation:

There is some info missing. I think this is the original question.

<em>A chemistry student needs 20.0g of acetic acid for an experiment. He has 400.g  available of a 40.5 %  w/w solution of acetic acid in acetone.  </em>

<em> Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.</em>

<em />

We have 400 g of solution and there are 40.5 g of solute (acetic acid) per 100 grams of solution. We can use this info to find the mass of acetic acid in the solution.

400gSolution \times \frac{40.5gSolute}{100gSolution} = 162 g Solute

Since we only need 20.0 g of acetic acid, there is enough of it in the solution. The mass of solution that contains 20.0 g of solute is:

20.0gSolute \times \frac{100gSolution}{40.5gSolute} = 49.4g Solution

4 0
3 years ago
How to tell if a reaction is double bond or single
Alenkasestr [34]

Answer:

Single replacement is a reaction in which one element reacts with another compund to form another compound and another element.

planation:

6 0
3 years ago
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