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stellarik [79]
2 years ago
11

Use the image above to answer the question: Roger collected four rock samples and wrote a description of how each was formed. Wh

ich of the following rocks that Roger collected is a metamorphic rock?
A. Formed from magma that cooled slowly
B. Formed by pressure and heat over time
C. Formed from lava that cooled quickly
D. Formed by pieces of rock cemented together

Chemistry
2 answers:
kati45 [8]2 years ago
7 0

Answer  THE ANSWER IS B

Explanation:

Cause metamorphic rock is formed by heat pressure overtime

IrinaVladis [17]2 years ago
4 0

Answer:

B

Explanation:

Cause metamorphic rock is formed by heat pressure overtime

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4.50 g of NaCl reacts with 10.00 g of AgNO3 to produce 7.93 g of AgCl. If the theoretical amount of AgCl that can be formed is 8
olga nikolaevna [1]

Answer: 94.07%

Explanation:

Percentage yield can be calculated by the formula

%yield = Experimental yield/Theoretical yield x100

Experimental yield = 7.93g

Theoretical yield = 8.43

%yield = Experimental yield/Theoretical yield x100

%yield = 7.93/8.43 x 100 = 94.07%

4 0
3 years ago
If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
Helen [10]

This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0
2 years ago
How much heat is required to increase the temperature of 10.0 grams of water 6.0oC? (The specific heat of water is 4.18 J/g x oC
scoray [572]

Heat required in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:<span>

Heat = mC (T2-T1)
Heat = 10.0 g (4.18 J/g-C ) ( 6.0 C )
<span>Heat = 250.8 J</span></span>

8 0
3 years ago
If you reacted 183 grams of copper sulfate with excess iron, what mass of copper would you expect to make? You may need to balan
Nezavi [6.7K]

The question does not provide the equation

Answer:-

72.89 grams

Explanation:-

The balanced chemical equation for this reaction is

CuSO4 + Fe --> FeSO4 + Cu

Molecular weight of CuSO4 = 63.55 x 1 + 32 x 1 + 16 x 4

= 159.55 gram

Atomic weight of Cu = 63.55 gram.

According to the balanced chemical equation

1 CuSO4 gives 1 Cu

∴159.55 gram of CuSO4 would give 63.55 gram of Cu.

183 gram of CuSO4 would give 63.55 x 183 / 159.55

= 72.89 grams of Cu

7 0
3 years ago
Pcl5 exist but ncl5 does not.why?
jeyben [28]
N is as electronegative as Cl is. So Cl doesnt react with O, N
6 0
2 years ago
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