Question

The tables represent two linear functions in a system,

Answer 1

Answer:

(8, -22)

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

First table:

(-4, 26), (0, 10) → b = 10

$m=\dfrac{10-26}{0-(-4)}=\dfrac{-16}{4}=-4$

$\boxed{y=-4x+10}$

Second table:

(-4, 14), (0, 2) → b = 2

$m=\dfrac{2-14}{0-(-4)}=\dfrac{-12}{4}=-3$

$\boxed{y=-3x+2}$

We have the system of equations:

$\left\{\begin{array}{ccc}y=-4x+10&(1)\\y=-3x+2&(2)\end{array}\right\\\\\text{Put (1) to (2):}\\\\-4x+10=-3x+2\qquad\text{subtract 10 from both sides}\\-4x=-3x-8\qquad\text{add 3x to both sides}\\-x=-8\qquad\text{change the signs}\\x=8\\\\\text{Put the value of x to (2):}\\\\y=-3(8)+2\\y=-24+2\\y=-22$