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raketka [301]
3 years ago
15

(5x + k)2 = mx2 + 70x + 49 Find m Find k

Mathematics
1 answer:
blagie [28]3 years ago
4 0

Answer:

10x+2k=(2m+70) x + 49

10= 2m+70

2m=-60

m = -30

2k=49

k= 49/2

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Oliga [24]

Answer:

2 is your answer.

Step-by-step explanation:

Simplify. Remember to follow PEMDAS. First solve the parenthesis, then multiply, and finally divide.

-8(17 - 12) = -8(5) = -40

-2(8 - (-2)) = -2(8 + 2) = -2(10) = -20

-40/-20 = 2

2 is your answer.

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3 years ago
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The slope of a line is –2 and its y-intercept is (0, 3). What is the equation of the line that is parallel to the first line and
Doss [256]

Answer:

The answer is A) 2x + y  = 6

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This is answer A

4 0
4 years ago
How do you determine a function if a relation is a function <br>​
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Answer:

Hello! A function is easily identified when an x value does not have more than 1 y value. a y value can have as many x values to infinity, but x can only have one y.

Example...

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7 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 437437 green peas and 129129 yellow peas. Use
navik [9.2K]

Answer:

The null hypothesis: \mathbf{H_o: p=0.27}

The alternative hypothesis: \mathbf{H_1: p \neq 0.27}

Test statistics : z = −2.30

P-value:  = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and  conclude that under the same​ circumstances the proportion of offspring peas will be yellow is not equal to 0.27

Step-by-step explanation:

From the given information:

Let's state the null and the alternative hypothesis;

Since The claim is that 27%  of the offspring peas will be yellow.

The null hypothesis state that the proportion of offspring peas will be yellow is equal to 0.27.

i.e

\mathbf{H_o: p=0.27}

The alternative hypothesis  state that the proportion of offspring peas will be yellow is not equal to 0.27

\mathbf{H_1: p \neq 0.27}

<u>The test statistics:</u>

we are given 437 green peas and 129 yellow apples;

Hence;

\hat p = \dfrac{x}{n}

where ;

\hat p = sample proportion

x = number of success

n = total number of the sample size

\hat p = \dfrac{129}{437+129}

\hat p = \dfrac{129}{566}

\mathbf{\hat p = 0.2279}

Now; the test statistics can be computed as :

z = \dfrac { \hat p -p }{\sqrt {\dfrac{p(1-p)}{n}  } }

z = \dfrac {0.2279 -0.27 }{\sqrt {\dfrac{0.27(1-0.27)}{566}  } }

z = \dfrac {-0.043 }{\sqrt {\dfrac{0.27(0.73)}{566}  } }

z = \dfrac {-0.043 }{\sqrt {\dfrac{0.1971}{566}  } }

z = \dfrac {-0.043 }{\sqrt {3.48233216*10^{-4} } }

z = \dfrac {-0.043 }{0.01866} }

z = −2.30

C. P-value

P-value = P(Z < z)

P-value = P(Z< -2.30)

By using the ​ P-value method and the normal distribution as an approximation to the binomial distribution.

from the table of standard normal distribution

move left until the first column is reached. Note the value as –2.0

move upward until the top row is reached. Note the value as 0.30

find the probability value as 0.010724 by the intersection of the row and column values gives the area to the left of

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P- value = 2P(z ≤ -2.30)

P-value = 2 × 0.01072

P - value = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and  conclude that under the same​ circumstances the proportion of offspring peas will be yellow is not equal to 0.27

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3 years ago
Alex has 905 stickers. some of them are animal stickers and the rest of them are airplanes stickers. how many of each could he h
Nookie1986 [14]
You could solve this by doing 905 divided by the total of animal stickers
6 0
4 years ago
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