Answer:
So, the odds that a taxpayer would be audited 28 to 972 or 2.88%
Step-by-step explanation:
Given
Let P(A) = Probability of irs auditing
P(A) = 2.8%
Let n = number of those who earn above 100,000
To get the odds that taxpayer would be audited, we need to first calculated the proportion of those that will be audited and those that won't.
If the probability is 2.8% then 2.8 out of 100 will be audited. That doesn't make a lot of sense since you can't have 2.8 people; we multiply the by 10/10
i.e.
Proportion, P = 2.8/100 * 10/10
P = 28/1000
The proportion of those that would not be audited is calculated as follows;
Q = 1000 - P
By substituton
Q = 1000 - 28
Q = 972
So, the odds that a taxpayer would be audited 28 to 972 or P/Q
P/Q = 28/972
= 0.0288065844
= 2.88% --- Approximately
Find the median of each set:-
Median is middle number of a data set. If a data set has an odd number of numbers then the median is the middle number when ordered form least to greatest but if its an even number you have to find the mean for the middle 2 numbers when ordered for least to greatest.
A.
1.2, 2.4, 3.2, 3.2, 3.6, 4.0, 4.1, 4.7
Even numbers = 8
3.2 + 3.6 = 6.8
6.8 ÷ 2 =
Median = 3.4
So this shows that A isn't the answer because the median of A is 3.4, not 3.2.
B.
1.6, 2.8, 2.9, 3.1, 3.3, 3.6, 4.2, 4.5
Even numbers = 8
3.1 + 3.3 = 6.4
6.4 ÷ 2 = 3.2
Median = 3.2
<span>So this shows that B is the answer because the median of B is 3.2.
C.
1.8, 2.0, 2.0, 2.2, 3.2, 4.7, 4.8, 4.9
</span>
Even numbers = 8
2.2 + 3.2 = 5.4
5.4 ÷ 2 = 2.7
Median = 2.7
<span>So this shows that C isn't the answer because the median of C is 2.7, not 3.2.
</span>
D.
1.4, 1.7, 2.9, 3.0, 3.1, 3.2, 3.2, 3.2, 4
Odd numbers = 9
Median = 3.1
<span>So this shows that D isn't the answer because the median of D is 3.1, not 3.2.
</span>
The stem and leaf plot which median is 3.2 is B.
I'm pretty sure it is 155
The simplified expression is 16
The answer for the algebraic expression is 5-6t