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3 years ago

What is the slope of 2y-2x=2

Mathematics

2 answers:

Anastaziya [24]3 years ago

6 0

Answer:

m = 1

Step-by-step explanation:

To easily find the slope of this equation, let's change it to slope-intercept form, y = mx + b.

2y - 2x = 2

Adding 2x to both sides, the equation becomes 2y = 2x + 2.

Dividing both sides by 2, the equation becomes y = x + 1.

The coefficient of x is the slope, and since there is no visible coefficient, that means the slope is 1 (AKA, x is being multiplied by 1).

vodomira [7]3 years ago

6 0

Answer:

Step-by-step explanation:

2y - 2x = 2

2y = 2x + 2

y = 2x/2 + 2/2

y = x + 1

Slope =1

{Compare with y =mx +b}

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Pls answer this asap

denis23 [38]

Answer:

y = - $\frac{3}{2}$ x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (2, 0) ← 2 points on the line

m = $\frac{0-3}{2-0}$ = - $\frac{3}{2}$

The line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = - $\frac{3}{2}$ x + 3 ← equation of line

5 0

3 years ago

Find the smallest set of three consecutive even whole numbers whose sum is greater than twice the middle integer.

gizmo_the_mogwai [7]

Answer:

72,80,178 , hope this helped

4 0

3 years ago

Read 2 more answers

Please help

Murrr4er [49]

<h3>You have the correct answer. It is choice B. Nice work.</h3>

K is the midpoint, so $\overline{IK} \cong \overline{GK}$ and $\overline{JK} \cong \overline{HK}$ , and along with the congruent vertical angles ( $\angle GKH \cong \angle IKJ$ and $\angle GKJ \cong \angle IKH$ ), you would use the SAS (side angle side) congruence theorem to prove the inner pairs of triangles to be congruent.

So, $\triangle HKG \cong \triangle JKI$ (top and bottom triangles) and $\triangle GKJ \cong \triangle IKH$ (left and right triangles).

Then through CPCTC, we can show the corresponding pieces are congruent leading to $\overline{GH} \cong \overline{JI}$ and $\overline{GJ} \cong \overline{HI}$ showing the opposite sides of the quadrilateral are congruent. Therefore we do have a parallelogram and enough information to prove it as such.