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3 years ago

Please Help.. 1) Which Choice shows The Values from greatest to least

Mathematics

2 answers:

EleoNora [17]3 years ago

8 0

Answer: C

Step-by-step explanation: 6 being positive will be first, so you can already get rid of A and B. To find the order of the next numbers, know that in negative numbers, the higher the number is, the lower its actual value is.

irakobra [83]3 years ago

3 0

C because it positive are the greatest and negatives are lower and go lesser from 0 down.

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A square classroom has a perimeter of 60 feet. How long is each side of the room?

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Answer:

Step-by-step explanation:

since it is a square all sides are equal.

60/4=15

Therefore the answer is 15

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Answer:

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3 years ago

Find the volume of a rectangular prism that is 8 inches high, 12 inches long, and 5 inches wide.

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3 years ago

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Find the solution of the system of equations. 3x+y=-15 <br>3x+2y=-18

s344n2d4d5 [400]

Answer:

(x, y) ==> (-4, -3)

Step-by-step explanation:

-2(3x + y = -15) ==> -6x - 2y = 30

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-6x - 2y = 30

3x + 2y = -18

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/-3 /-3

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Now, we solve for y:

-6x - 2y = 30

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Hope this helps!

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2 years ago

Express the number 220 as the sum of four numbers that form a geometric progression such that the third term is greater than the

siniylev [52]

Answer:

Step-by-step explanation:

The first four terms of geometric series is:

$a,ar,ar^2,ar^3$

Since, we have given information that the third number is greater than 44 that means:

$ar^2=a+44$

Above equation can be rewritten as:

$a(r^2-1)=44$

Now, using:

$a^2-b^2=(a+b)(a-b)$

Here, a=r,b=1

$a(r+1)(r-1)=44$ (1)

The sum of first four terms is:

$a+ar+ar^2+ar^3=220$

$a(1+r+r^2+r^3)=220$

$a(1(1+r)+r^2(1+r))=220$

$a((1+r)(1+r^2))=220$ (2)

Divide equation (2) by (1) we get:

$\frac{r^2+1}{r-1}=\frac{220}{44}$

$r^2+1=5r-5$

$\Rightarrow r^2-5r+6=0$

$\Rightarrow r^2-3r-2r+6=0$

$\Rightarrow r(r-3)-2(r-3)=0$

$\Rightarrow (r-2)(r-3)=0$

$\Rightarrow r=2,3$

CASE1: When r=2 in $ar^2=a+44$

$a(4)=a+44$

$3a=44$

$a=\frac{44}{3}$

CASE2:When r=3 in $ar^2=a+44$

$a(3)^2=a+44$

$\Rightarrow 9a=a+44$

$\Rightarrow 8a=44$

$\Rightarrow a=\frac{44}{8}=\frac{11}{2}$

The series becomes:

From CASE1: $\frac{44}{3},\frac{44\cdot 2}{3},\frac{44\cdot 2^2}{3},\frac{44\cdot 2^3}{3}$

$\Rightarrow \frac{44}{3},\frac{88}{3},\frac{176}{3},\frac{352}{3}$

From CASE2: $\frac{11}{2},\frac{11\cdot 3}{2},\frac{11\cdot 3^2}{2},\frac{11\cdot 3^3}{2}$

$\Rightarrow \frac{11}{2},\frac{33}{2},\frac{99}{2},\frac{297}{2}$

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3 years ago

Read 2 more answers

Please Help.. 1) Which Choice shows The Values from greatest to least​

Please Help.. 1) Which Choice shows The Values from greatest to least