All categories

3 years ago

Which number sentence shows the correct placement of the decimal point in the product, based on the two factors?

Mathematics

1 answer:

aliina [53]3 years ago

7 0

3.48 x 42.37 = 147.4476

You might be interested in

Six students all took the same test. Their scores were 70,71,75,75,88, and 89. What is the mean absolute deviation for the test

ki77a [65]

Answer:D)78

Step-by-step explanation:70+71+75+75+88+89/6

5 0

3 years ago

The approximate value of 5,700,000 x 200 is

vampirchik [111]

Answer:

1,140,000,000

Step-by-step explanation:

4 0

3 years ago

I need help with question 5 show your work.Also tell me if my divison for question 6 is correct.Thx.P.S.I Will give the brainlie

Sloan [31]

5. Start by finding how many tiles make up the outer edge of the pool. We know that each tile is 3/4 foot, and that the entire length is 12 feet. So by doing a division, we'll find how many tiles there are:
12 ÷ 3/4 = 16. By looking at the picture, we can confirm this. By looking at the picture we also see that the pool is the same length as 14 tiles, so the fraction is 14/16 -> 7/8.

7 0

3 years ago

Read 2 more answers

Solve for x. 4x^3 = 2x^-1

tekilochka [14]

x
=
4
√
8
2
,
−
4
√
8
2
x
=
8
4
2
,
-
8
4
2

7 0

3 years ago

Read 2 more answers

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0

3 years ago