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3 years ago

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Because the charges on the plates of a parallel-plate capacitor are opposite in sign, they attract each other. Hence, it would t

ake positive work to increase the plate separation. What type of energy in the system changes due to the external work done in this process?

1 answer:

melisa1 [442]3 years ago

7 0

Answer:

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Explanation:

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What are light years actually? answer in brief

a_sh-v [17]

A light year is a distance.
It's the distance that light travels in a year, through vacuum.
The distance is about 5.875 trillion miles.
The nearest star outside our solar system is about 4.2 light years from us.

Sorry to have rambled on for so long.

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3 years ago

When resistance is decreased in a circuit, current will _________.

Mars2501 [29]

The answer is A. Increase

The formula is <span>Voltage = Resistance X Current

Lets say the voltage is 10 and the resistence is 5

10 = 5 x current
Current = 2

Now, lets decrease the resistence from 5 to 2

10 = 2 x Current
Current = 5

The current increases
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3 years ago

A helix with 17 turns has height H and radius R. Charge is distributed on the helix so that the charge density increases like (i

marishachu [46]

The total charge on the helix is

Q = $\frac{221}{2}\sqrt{(\frac{H}{17})^2+(2\piR)^2$

Height of one turn = $\frac{H}{n}$

Horizontal distance in one turn = $2\pi R$

<h3>length of spring in one turn is</h3>

$l = \sqrt{h^2+(2\piR)^2}\\\\
l = \sqrt{(\frac{H}{n})^2+(2\piR)^2}
$

So, the total length of spring

$L = n*l\\\\
L = n * \sqrt{(\frac{H}{n})^2+(2\piR)^2}
$

Therefore, charge on spring

$Q = \frac{1}{2}*L*(13-0)\\\\
Q = \frac{1}{2}*n\sqrt{(\frac{H}{n})^2+(2\piR)^2}*13\\\\
Q = \frac{1}{2}*17*13\sqrt{(\frac{H}{17})^2+(2\piR)^2}\\\\
Q = \frac{221}{2}\sqrt{(\frac{H}{17})^2+(2\piR)^2\\\\
$

For more information on linear charge density, visit

brainly.com/question/15359786

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2 years ago

A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =

Ratling [72]

Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

$v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2$

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

$v = \omega R\\a = \alpha R$

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

$v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft$

One revolution is equal to the circumference of the drum. So, total number of revolutions is

$x / (2\pi R) = 6/(\pi R)$

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

$a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2$

b) $a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2$

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4 years ago

Explain what was ultimately responsible for London’s “killer fog” in 1952.

stellarik [79]

Answer:

possible answer from edge

Explanation:

After World War II the only coal available to burn residentially, either for cooking or warmth, was of poor quality and contained large amounts of contaminants that made its fumes toxic. So when millions of homes in London burned this low quality coal and the local atmosphere over and around London stagnated, there was nowhere for the fumes to go. This stagnation allowed the toxic coal fumes to build up until they became physically harmful to humans and animals.

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3 years ago

Read 2 more answers