Can anyone help with this? Would appreciate it!
1 answer:
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Given:
Slips of paper numbered 1 to 15 are placed in a box.
To find:
The probability that the number picked is either a multiple of 5 or an odd number.
Solution:
We have,
Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
No. of total outcomes = 15
Multiple of 5 are 5, 10, 15.
Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.
Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.
No. of favorable outcomes = 9
We know that,
Therefore, the probability that the number picked is either a multiple of 5 or an odd number is 0.6.
Hey!
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x – 3y = 3 is written in standard form. We can write in the slope-intercept form.
x - 3y = 3
x - 3y - x = 3 - x
3y = 3 - x
3y/3 = 3/3 - 3/x
y = 1 - 3/x
y = 1/3x - 1
Now, we know that the y-intercept is -1 and the slope is 1/3
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Hence, the answer is
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Hope This Helped! Good Luck!
