Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
D 28/4=7 that is the answer for the question
Answer: 7 4/9
Step-by-step explanation:
Find least common denominator of 3 and 9, which is 9. So, 11 1/9 - 3 6/9 = 7 4/9
Answer:
(x+6)^2+3
Step-by-step explanation:
translate 6 left
left is negative
so (x+6)^2. it is + because the x goes in the opposite direction causing (x-6)^2 to go right
and 3 units up so add x by 3 to get (x+6)^2+3
Cosa/1+sina + 1+sina/cosa = (cos^2a+1+2sina+sin^2a)/(cosa)((1+sina)
=( 1+1+2sina)/(cosa) (1+sina)
=2(1+sina)/ (cosa) (1+sina)
=2/cosa
=2sec a (verified)
