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ruslelena [56]
3 years ago
9

Hello can someone help me with this?

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

Answer:

  1. 1
  2. 1/2
  3. 1/5
  4. 2
  5. 10
  6. 0
  7. -1
  8. -1/2
  9. -1/5
  10. -2
  11. -10

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15.What must be subtracted from x 3 + 3x-8 to 2x 3 +x 2 -4x+2
Alik [6]

Answer:

Step-by-step explanation:

2 x 3−3 x 2+ x −30=0 ... The groups have no common factor and can not be added up to form a multiplication. Polynomial Roots Calculator : 3.3 Find roots (zeroes) of : F(x) = 2x3-3x2+x-30 ... Subtract 5 from both side of the equation : ... abc. a. x. y. /. |abs|. ( ). 7. 8. 9. *. 4. 5. 6. -. %. 1. 2. 3. +. <. > 0. , . = abc. a. b. c. d. e.

8 0
3 years ago
PLEASE HELP ME!! I’m already stressed out and I don’t need people getting on here just for points
Arte-miy333 [17]

Answer:

78.5

Step-by-step explanation:

Formula to find area of a circle: A= pi*raduis to the second power

3.14*5^{2}

First you square the 5

You do this by multiplying 5 times itself

3.14*25

Then you multilpy 3.14 and 25

78.5

7 0
3 years ago
Quadrant:
NISA [10]

<h2>✒️Area Between Curves</h2>

\small\begin{array}{ |c|c} \hline \bold{Area\ Between\ Curves} \\ \\ \textsf{Solving for the intersection of }\rm y = x^2 + 2\textsf{ and }\\ \rm y = 4, \\ \\ \qquad \begin{aligned} \rm y_1 &=\rm y_2 \\ \rm x^2 + 2 &=\rm 4 \\ \rm x^2 &= \rm 2 \\ \rm x &=\rm \pm \sqrt{2} \end{aligned} \\ \\ \textsf{We only need the first quadrant area bounded} \\ \textsf{by the given curves so the integral for the area} \\ \textsf{would then be} \\ \\ \boldsymbol{\displaystyle \rm A = \int_{\ a}^{\ b} {\left( \begin{array}{c}\text{upper} \\ \text{function}\end{array} \right) - \left( \begin{array}{c} \text{lower} \\ \text{function} \end{array} \right)\ dx}} \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} \Big[4 - (x^2 + 2)\Big]\ dx \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} (2 - x^2)\ dx \\ \\ \rm A = \left[2x - \dfrac{x^3}{3}\right]_{0}^{\sqrt{2}} \\ \\ \rm A = 2\sqrt{2} - \dfrac{\big(\sqrt{2}\big)^3}{3} \\ \\ \rm A = 2\sqrt{2} - \dfrac{2\sqrt{2}}{3} \\ \\\red{\boxed{\begin{array}{c} \rm A = \dfrac{4\sqrt{2}}{3}\textsf{ sq. units} \\ \textsf{or} \\ \rm A \approx 1.8856\textsf{ sq. units} \end{array}}} \\\\\hline\end{array}

#CarryOnLearning

#BrainlyForTrees

\qquad\qquad\qquad\qquad\qquad\qquad\tt{Monday\:at \: 04-04-2022} \\ \qquad\qquad\qquad\qquad\qquad\qquad\tt{12:10 \: pm}

5 0
2 years ago
How good are you setting goals? 3 sentences for honors
Lunna [17]

Answer:

Be more productive

Step-by-step explanation:

This could be a goal

5 0
3 years ago
Multiply 8 by the sum of 4 and 2
Fudgin [204]

Answer:

48

Step-by-step explanation:

so we just have to set up this expression

it would be

8(4+2)

this would be

8(6)

this equals 48

6 0
3 years ago
Read 2 more answers
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