Question

A sphere has a radius of 6 meters. A second sphere has a radius of 3 meters. What is the difference of the volumes of the spheres?

Answer 1

∆volume = 4/3 *pi * (R^3 -r^3 )
= 4/3 *pi*((6)^3 -(3)^3)
= 252*pi
= 791.68 m^3

Answer 2

Answer:

$791. 28 m^3$

Step-by-step explanation:

Volume of sphere with 6 meter radius

$= \frac{4}{3} \pi r^3\\= \frac{4}{3} (3.14) ( 6^3)\\= 904.32 m^3$

Volume of sphere with 3 meter radius

$= \frac{4}{3} \pi r^3\\= \frac{4}{3} (3.14) ( 3^3)\\= 113.04 m^3$

Difference between the volume of two sphere

$= (904 .32 m^3)- ( 113.04 m^3)\\= 791.28 m^3$