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Vera_Pavlovna [14]
3 years ago
15

13 men can weave 117 baskets in a week how many men will need to be 189 baskets in 3days​

Mathematics
2 answers:
enyata [817]3 years ago
7 0

Answer:

49 men will be required to weave 189 baskets in 3 days.

yarga [219]3 years ago
5 0

Answer:

49 men required

Step-by-step explanation:

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I NEED THIS ASAP!!!!!!!!!!!!
Artyom0805 [142]

Answer:

we are going to use the formula...
V=πr2h

Step-by-step explanation:

so

V = (3.14) 4x4 (9)

V = (3.14) 16 x 9

V = 3.14 x 144

V = 452.16

Hence, the third or C

8 0
2 years ago
The cycling team is ranked by the total time it takes its team members to
hodyreva [135]

Answer:2 hrs

Step-by-step explanation:

x+2x+3x=12

6x=12

x=2

5 0
3 years ago
Tell multiple ways to write 65% as a fraction
xxMikexx [17]
65/100 or 13/20
Both work, it's just that 13/20 is simplified
8 0
3 years ago
Read 2 more answers
If $396 is invested at an interest rate of 13% per year and is compounded continuously, how much will the investment be worth in
Ipatiy [6.2K]

Answer:

A=\$584.88  

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

t=3\ years\\ P=\$396\\ r=0.13  

substitute in the formula above  

A=\$396(e)^{0.13*3}=\$584.88  

3 0
3 years ago
Read 2 more answers
Consider the probability that exactly 90 out of 148 students will pass their college placement exams. Assume the probability tha
Pepsi [2]

Answer:

0.0491 = 4.91% probability that exactly 90 out of 148 students will pass their college placement exams.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

Assume the probability that a given student will pass their college placement exam is 64%.

This means that p = 0.64

Sample of 148 students:

This means that n = 148

Mean and standard deviation:

\mu = E(X) = np = 148(0.64) = 94.72

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{148*0.64*0.36} = 5.84

Consider the probability that exactly 90 out of 148 students will pass their college placement exams.

Due to continuity correction, 90 corresponds to values between 90 - 0.5 = 89.5 and 90 + 0.5 = 90.5, which means that this probability is the p-value of Z when X = 90.5 subtracted by the p-value of Z when X = 89.5.

X = 90.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{90.5 - 94.72}{5.84}

Z = -0.72

Z = -0.72 has a p-value of 0.2358.

X = 89.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{89.5 - 94.72}{5.84}

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.2358 - 0.1867 = 0.0491.

0.0491 = 4.91% probability that exactly 90 out of 148 students will pass their college placement exams.

5 0
2 years ago
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