HELP ME PLEASE HURRY: Wade has claims that quadrilateral ABCD is a square because he has found that all four sides are congruent
as shown below:
AB = 8.3 units
BC = 8.3 units
CD= 8.3 units
AD = 8.3 units
Explain in at least two sentences why Wade is incorrect and what else he needs to show for ABCD to be a square. Be specific!
1 answer:
Answer:
At first we should know that:
<u>The properties of the square are:</u>
- It has four equal sides.
- All angles are right angles or equal to 90º.
- The sum of its all angles is 360º
- It has two pairs of perpendicular lines.
- It has two pairs of parallel lines.
<u>The properties of Rhombus</u>
- It has equal four sides.
- The opposite sides are of the same length.
- It has two acute angles and two obtuse angles.
- The sum of its all angles is 360º
- It has zero pairs of perpendicular lines.
- It has two pairs of parallel lines.
So, Wade is incorrect because the quadrilateral may be <u>Rhombus</u>
And the quadrilateral to be a square, she needs to show that It has two pairs of perpendicular lines.
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