Answer:
1. x = 2√3 or 3.46
2. y = 4√3 or 6.93
3. z = 4√6 or 9.80
Step-by-step explanation:
1. Determination of the value of x.
Angle (θ) = 60°
Opposite = 6
Adjacent = x
Tan θ = Opposite /Adjacent
Tan 60 = 6 / x
√3 = 6/x
Cross multiply
x√3 = 6
Divide both side by √3
x = 6 / √3
Rationalise
x = (6 / √3) × (√3/√3)
x = 6√3 / 3
x = 2√3 or 3.46
2. Determination of the value of y.
Angle (θ) = 60°
Opposite = 6
Hypothenus = y
Sine θ = Opposite /Hypothenus
Sine 60 = 6/y
√3/2 = 6/y
Cross multiply
y√3 = 2 × 6
y√3 = 12
Divide both side by √3
y = 12/√3
Rationalise
y = (12 / √3) × (√3/√3)
y = 12√3 / 3
y = 4√3 or 6.93
3. Determination of the value of z.
Angle (θ) = 45°
Opposite = y = 4√3
Hypothenus = z
Sine θ = Opposite /Hypothenus
Sine 45 = 4√3 / z
1/√2 = 4√3 / z
Cross multiply
z = √2 × 4√3
z = 4√6 or 9.80
So then there are about 15-20 doctors
Answer:
I'm pretty sure it's c but I'm not sure
Answer:
The most correct option for the recursive expression of the geometric sequence is;
4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2
Step-by-step explanation:
The general form for the nth term of a geometric sequence, aₙ is given as follows;
aₙ = a₁·r⁽ⁿ⁻¹⁾
Where;
a₁ = The first term
r = The common ratio
n = The number of terms
The given geometric sequence is 7, 14, 28, 56, 112
The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2
r = 2
Let, 't₁', represent the first term of the geometric sequence
Therefore, the nth term of the geometric sequence is presented as follows;
tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾
tₙ = t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁
∴ tₙ = 2·tₙ₋₁, for n ≥ 2
Therefore, we have;
t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.
Answer:
2x-32
Step-by-step explanation:
You would distribute the 4.