Answer:
8/17 is correct because cosine = adjacent/hypotenuse, and since angle A is theta, or the reference angle, the adjacent of A would be 8, and the hypotenuse is always across the right angle.
15/17 would be sine instead of cosine

And
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So :

And

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So to find g(x) , we must find the inverse of f(x) .
Let's do it .....


Subtract the sides of the equation minus 1

Divided the sides of the equation by 8

From the sides of the equation, we take the radical with interval 3
![\sqrt[3]{ \frac{y - 1}{8} } = x \\](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7By%20-%201%7D%7B8%7D%20%7D%20%3D%20x%20%5C%5C%20%20)
![\sqrt[3]{ \frac{1}{8}(y - 1) } = x \\](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B1%7D%7B8%7D%28y%20-%201%29%20%7D%20%3D%20x%20%5C%5C%20%20)
![\frac{1}{2} \sqrt[3]{y - 1} = x \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%5Csqrt%5B3%5D%7By%20-%201%7D%20%3D%20x%20%5C%5C%20%20%20)
![\frac{ \sqrt[3]{y - 1} }{2} = x \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7By%20-%201%7D%20%7D%7B2%7D%20%3D%20x%20%5C%5C%20%20)
So ;
![{f}^{ - 1}(x) = \frac{ \sqrt[3]{x - 1} }{2} \\](https://tex.z-dn.net/?f=%20%7Bf%7D%5E%7B%20-%201%7D%28x%29%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7Bx%20-%201%7D%20%7D%7B2%7D%20%5C%5C%20%20%20%20)
Now we find g(x) which is :
![g(x) = \frac{ \sqrt[3]{x - 1} }{2} \\](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7Bx%20-%201%7D%20%7D%7B2%7D%20%5C%5C%20%20)
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And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Answer:
r = 13
Step-by-step explanation:
The first step is to find b from y=mx=b using m=4/3 and (-4,8)

After solving the equation, b will equal -16/3 making the final equation be

Using the equation, you can solve for r.

This will bring the answer being r = 13
Answer:
choice a.) degree 3, constant term -1 leading coefficient 1
Step-by-step explanation:
expand the binomial product
(x - 1)(xx + 1) = xxx - 1 + x - xx