X will equal 14 because the ration between two of them are 2:1. Hope it help!
Answer:
Jaden broke it and the real answer is $1 and 27 cents
Step-by-step explanation:
Question :-
- A Triangle has an Area of 48 cm² . The Height of the Triangle is 6 cm . What is the Base of the Triangle ?
Answer :-
- Base of Triangle is 16 cm .
Explanation :-
As per the provided information in the given question, we have been given that the Area of Triangle is 48 cm² . It's Height is given as 6 cm . And, we have been asked to calculate the Base of Triangle .
For calculating the Base of Triangle , we will use the Formula :-
![\bigstar \: \: \: \boxed{ \sf{ \: Area \: _{Triangle} \: = \: \frac{1}{2} \: \times \: B \: \times \: H \: }}](https://tex.z-dn.net/?f=%20%5Cbigstar%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Cboxed%7B%20%5Csf%7B%20%5C%3A%20Area%20%5C%3A%20_%7BTriangle%7D%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%5Cfrac%7B1%7D%7B2%7D%20%5C%3A%20%20%5Ctimes%20%20%5C%3A%20B%20%5C%3A%20%20%5Ctimes%20%20%5C%3A%20H%20%5C%3A%20%20%7D%7D%20)
Where ,
- B denotes to the Base .
- H denotes to the Height .
Therefore , by Substituting the given values in the above Formula :-
![\dag \: \: \: \sf { Area \: _{Triangle} \: = \: \dfrac{1}{2} \: \times \: Base \: \times \: Height }](https://tex.z-dn.net/?f=%20%5Cdag%20%5C%3A%20%5C%3A%20%5C%3A%20%5Csf%20%7B%20Area%20%5C%3A%20_%7BTriangle%7D%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%5Cdfrac%7B1%7D%7B2%7D%20%5C%3A%20%20%5Ctimes%20%20%5C%3A%20Base%20%5C%3A%20%20%5Ctimes%20%20%5C%3A%20Height%20%7D%20)
![\longmapsto \: \: \: \sf {48 \: = \: \dfrac {1}{2} \: \times \: Base \: \times \: 6 }](https://tex.z-dn.net/?f=%20%5Clongmapsto%20%5C%3A%20%5C%3A%20%5C%3A%20%5Csf%20%7B48%20%5C%3A%20%3D%20%5C%3A%20%5Cdfrac%20%7B1%7D%7B2%7D%20%5C%3A%20%5Ctimes%20%5C%3A%20Base%20%5C%3A%20%5Ctimes%20%5C%3A%206%20%7D%20)
![\longmapsto \: \: \: \sf {48 \: \times \: 2 \: = \: 1 \: \times \: Base \: \times \: 6}](https://tex.z-dn.net/?f=%20%5Clongmapsto%20%5C%3A%20%5C%3A%20%5C%3A%20%5Csf%20%7B48%20%5C%3A%20%5Ctimes%20%5C%3A%202%20%5C%3A%20%3D%20%5C%3A%201%20%5C%3A%20%5Ctimes%20%5C%3A%20Base%20%5C%3A%20%5Ctimes%20%5C%3A%206%7D%20)
![\longmapsto \: \: \: \sf {96 \: = \: 1 \: \times \: Base \: \times \: 6}](https://tex.z-dn.net/?f=%20%5Clongmapsto%20%5C%3A%20%5C%3A%20%5C%3A%20%5Csf%20%7B96%20%5C%3A%20%3D%20%5C%3A%201%20%5C%3A%20%5Ctimes%20%5C%3A%20Base%20%5C%3A%20%5Ctimes%20%5C%3A%206%7D%20)
![\longmapsto \: \: \: \sf {96 \: = \: 6 \: \times \: Base }](https://tex.z-dn.net/?f=%20%5Clongmapsto%20%5C%3A%20%5C%3A%20%5C%3A%20%5Csf%20%7B96%20%5C%3A%20%3D%20%5C%3A%206%20%5C%3A%20%5Ctimes%20%5C%3A%20Base%20%7D%20)
![\longmapsto \: \: \: \sf {Base \: = \: \dfrac {96}{6} }](https://tex.z-dn.net/?f=%20%5Clongmapsto%20%5C%3A%20%5C%3A%20%5C%3A%20%5Csf%20%7BBase%20%5C%3A%20%3D%20%5C%3A%20%5Cdfrac%20%7B96%7D%7B6%7D%20%7D%20)
![\longmapsto \: \: \: \textbf {\textsf {Base \: = \: 16 \: cm}}](https://tex.z-dn.net/?f=%20%5Clongmapsto%20%5C%3A%20%5C%3A%20%5C%3A%20%5Ctextbf%20%7B%5Ctextsf%20%7BBase%20%5C%3A%20%3D%20%5C%3A%2016%20%5C%3A%20cm%7D%7D%20)
Hence :-
- Base of Triangle = 16 cm .
![\underline {\rule {180pt} {4pt}}](https://tex.z-dn.net/?f=%20%5Cunderline%20%7B%5Crule%20%7B180pt%7D%20%7B4pt%7D%7D%20)
Question 1:
Density<span> (p) is equal to mass (m) divided by volume (V).
</span>
m = 4.9 g
V = 14 mL
So,
p =
![\frac{4.9}{14} = \frac{0.7}{2} = 0.35](https://tex.z-dn.net/?f=%20%5Cfrac%7B4.9%7D%7B14%7D%20%3D%20%20%5Cfrac%7B0.7%7D%7B2%7D%20%3D%200.35)
g/ML
Hence, the answer is A.
Question 2:
Volume = 5 * 2 * 1 = 10 cm³
All 3 blocks are the same which means their mass and volume are the same.
Hence, the density are equal.
Thus, the answer is D.
Question 3:
An intensive property is a physical quantity whose value does not depend on the amount of the substance<span> for which it is measured.
</span>
Hence, the answer is D.
Question 4:
You have to calculate the mass of each gas and then compare.
I'm not going to do that as it will take a lot of time.
Question 5:
Dense objects go down.
So the answer is D.
Honey is down and hence it is the most dense while the others are comparatively less dense since they float on top of the honey.