Regular heptagonSolve for <span>area
</span>A= 7/4 x a^2 x cot(180 degrees/7)
https://www.google.com/search?sourceid=chrome-psyapi2&rlz=1C1ZQQI_enUS697US697&ion=1&espv=2&ie=UTF-8&q=area%20of%20a%20heptagon%20formula&oq=area%20of%20a%20heptagon&aqs=chrome.1.69i57j0l5.4065j0j7
https://www.google.com/search?sourceid=chrome-psyapi2&rlz=1C1ZQQI_enUS697US697&ion=1&espv=2&ie=UTF-8<span>&q=area%20of%20a%20heptagon%20formula&oq=area%20of%20a%20heptagon&aqs=chrome.1.69i57j0l5.4065j0j7</span>
Answer:
The answer is option A, a double reflection
Answer:
276 guests were at the wedding
I believe it's 9.1 Hope this helps :)
So
if you assume that the month has 30 days and that the library opens at midnight, then
24 hours in a day
5 pm=12+5=17 hours
on wednessday=17-2=15 hours
wednessday=1/7 of week
so we find 1/7 of 30 which is 30/7=4 and 2/7
then subtract that from 30
30-4 and 2/7=25 and 5/7
ok so then we have
25 and 5/7 days is 17 hours and
4 and 2/7 days is 15 hours
so just multipy them and add
25 and 5/7 times 17=437.143 hours
4 and 2/7 days times 15 =64.2857
add
437.143+64.2856=501.429
so aprox 501.429
the real equation is
![[(\frac{1}{7})(n)(15)]+[ (\frac{6}{7}) (n)(17)]=hours](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B1%7D%7B7%7D%29%28n%29%2815%29%5D%2B%5B%20%28%5Cfrac%7B6%7D%7B7%7D%29%20%28n%29%2817%29%5D%3Dhours)
where n represents the number of days in the month
apros 501.429