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mariarad [96]
3 years ago
8

There is a bag filled with 3 blue and 5 red marbles.

Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer:

4/7

Step-by-step explanation:

The first time, the probability is 5/8. Then you remove one marble that is red (if you get a red one), so the probability is 4/7.

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The Thomas family budgeted 8% of their annual disposable income of $32,725 on clothes. Vincent was allowed 22% of the amount bud
barxatty [35]

Answer:

so first you add something and then subtract and then divide then you er butf then youcan see toplod ej

5 0
2 years ago
A family has two cars. The first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of
lesya692 [45]

Answer:

first car = 35, second car= 15

Step-by-step explanation:

40x+15y=1625

x+y=50

multiplying the 2nd by -15 and add the 2 equations, we get x= 35 and by substituting on second equation we get y= 15

4 0
3 years ago
How many duckling were swimming at the pond?
EleoNora [17]

Answer:

There are 20 ducklings.

Step-by-step explanation:

For every group of 6 ducks, 5 would be ducklings.

24 / 6 = 4

There are 4 groups of ducks.

5 * 4 = 20

4 0
3 years ago
An employer uses the linear regression equation y = 0.18 x + 320.22 to predict the weekly salary, y, of an employee who sells x
Nata [24]

Answer:

Option C is correct.

Alex earned about $60 more than Joaquin did.

Step-by-step explanation:

The linear regression equation

y = 0.18 x + 320.22

is used to predict the weekly salary, y, of an employee who sells x dollars worth of merchandise.

Joaquin sold $1500 worth of goods. Meaning that x for that week for Joaquin is 1500.

Joaquin' s salary for that week is then given as

y = 0.18x + 320.22

y = 0.18(1500) + 320.22 = 590.22

Hence, Joaquin's salary for that week = $590.22

Alex earns $650 that week. Meaning that y for Alex in that week = 650

y = 0.18x + 320.22

650 = 0.18x + 320.22

0.18x = 650 - 320.22 = 329.78

x = (329.78/0.18) = 1832.1

Hence, Alex sold goods worth $1832.1 that week.

Joaquin sold goods worth $1500

Joaquin earned $590.22

Alex sold goods worth $1832.1

Alex earned $650

From this calculation, it is evident that 'Alex earned about $60 more than Joaquin did' is the correct option as $650 is about $60 more than $590.22

Hope this Helps!!!

7 0
3 years ago
Read 2 more answers
Time spent using​ e-mail per session is normally​ distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that
liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 11, \sigma = 3

a. If you select a random sample of 25 ​sessions, what is the probability that the sample mean is between 10.8 and 11.2 ​minutes?

Here we have that n = 25, s = \frac{3}{\sqrt{25}} = 0.6

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.2 - 11}{0.6}

Z = 0.33

Z = 0.33 has a pvalue of 0.6293.

X = 10.8

Z = \frac{X - \mu}{s}

Z = \frac{10.8 - 11}{0.6}

Z = -0.33

Z = -0.33 has a pvalue of 0.3707.

0.6293 - 0.3707 = 0.2586

0.259 probability, rounded to three decimal places.

b. If you select a random sample of 25 ​sessions, what is the probability that the sample mean is between 10.5 and 11 ​minutes?

Subtraction of the pvalue of Z when X = 11 subtracted by the pvalue of Z when X = 10.5. So

X = 11

Z = \frac{X - \mu}{s}

Z = \frac{11 - 11}{0.6}

Z = 0

Z = 0 has a pvalue of 0.5.

X = 10.5

Z = \frac{X - \mu}{s}

Z = \frac{10.5 - 11}{0.6}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033.

0.5 - 0.2033 = 0.2967

0.297, rounded to three decimal places.

c. If you select a random sample of 100 ​sessions, what is the probability that the sample mean is between 10.8 and 11.2 ​minutes?

Here we have that n = 100, s = \frac{3}{\sqrt{100}} = 0.3

This probability is the pvalue of Z when X = 11.2 subtracted by the pvalue of Z when X = 10.8.

X = 11.2

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.2 - 11}{0.3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

X = 10.8

Z = \frac{X - \mu}{s}

Z = \frac{10.8 - 11}{0.3}

Z = -0.67

Z = -0.67 has a pvalue of 0.2514.

0.7486 - 0.2514 = 0.4972

0.497, rounded to three decimal places.

5 0
3 years ago
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