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Zigmanuir [339]
3 years ago
8

Which of the following could be used to describe the rate of a reaction?

Chemistry
2 answers:
lyudmila [28]3 years ago
3 0
Change in concentration/change in time.(C).
GarryVolchara [31]3 years ago
3 0

Answer:

Change in concentration / Change in time

Explanation:

Whenever the "rate" of something is being spoken about, "rate" always refers to a change in something divided by time.

If the rate of a reaction is increased, that means the reaction is going faster, and hence would take less time. So mathematically, if the rate is "something" divided by time, and time decreases, the overall fraction is going to be larger, meaning the rate is higher.

In a chemical reaction, there is always reactants and products. A lot of the time, the reactants are being converted to products, and during this process, the concentration of reactants decrease, while the concentration of the products increase. The only way that we can tell how fast the reaction is going, is by calculating the concentration of either the reactants or the products.

Hence, the rate of a reaction is the change in concentration / change in time.

You might be interested in
. The heat capacity of a bomb calorimeter was determined by burning 6.79 g methane (energy of combustion 802 kJ/mol CH4) in the
kolbaska11 [484]

Answer:

a) The heat capacity of the calorimeter is 31.4 kJ/ºC.

b) The energy of combustion of acetylene in kJ/mol is 1097 kJ/mol.

Explanation:

The heat capacity ( C ) of a substance is <em>the amount of heat required to raise the temperature  of a given quantity of the substance by one degree Celsius</em>. Its units are J/°C. or kJ/ºC.  

If we know the heat capacity and the amount of a substance, then the change in  the sample’s temperature (Δt ) will tell us the amount of heat (<em>q</em>) that has been absorbed  or released in a particular process. One of the equations for calculating the heat change is  given by:

q=C.ΔT

Where ΔT is the temperature change: ΔT= tfinal - tinitial, and C the heat capacity.

In the calorimeter, the heat given off by the sample is absorbed by the water and the bomb. The special design of the calorimeter enables us to assume that no heat (or mass) is lost to the surroundings during the time it takes to make measurements.

Therefore, we can call the bomb and the water in which it is submerged an isolated system. Because no heat enters or leaves the system throughout the process,  the heat change of the system ( q system ) must be zero and we can write:

qsystem = qrxn + qcal

qsystem = 0

where q cal and q rxn are the heat changes for the calorimeter and the reaction, respectively.  Thus, qrxn = -qcal

To calculate <em>q</em>cal , we need to know the heat capacity of the calorimeter ( Ccal ) and the  temperature rise, that is, <em>qcal = Ccal. ΔT</em>

a. The quantity Ccal is calibrated by burning a substance with an accurately known heat  of combustion. In order to do this, we need to convert the molar heat of combustion (expressed in kJ/mol) into heat of combustion (expressed in kJ). For that matter, we transform the 6.79 grams of methane into moles:

1 mol CH₄÷16.04 g CH₄ × 6.79 g CH₄ = 0.423 mol CH₄

And then multiply it by the molar heat of combustion:

802 kJ/mol × 0.423 mol = 339 kJ

Now we know that that the combustion of 6.79 g of methane releases 339 kJ of heat. If the temperature rise is 10.8ºC, then the heat capacity of the calorimeter is given by

Ccal= qcal/ΔT = 339 kJ/10.8ºC = 31.4 kJ/ºC

Once C cal has been determined, the calorimeter can be used to measure the heat of  combustion of other substances.  Note that although the combustion reaction is exothermic, q cal is a positive quantity because it represents the heat absorbed by the calorimeter.

b. The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with the same equation, and assuming no heat is lost to  the surroundings, we write

qcal=Ccal.ΔT= 31.4 kJ/°C × 16.9 °C = 531kJ

Now that we have the heat of combustion, we need to calculate the molar heat.   Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -531 kJ.

This is the heat released by the combustion of 12.6 g of acetylene ; therefore, we can write  the conversion factor as 531 kJ÷12.6 g

The molar mass of acetylene is 26.04 g, so the heat of combustion of 1 mole of acetylene is

 molar heat of combustion= -531 kJ÷12.6 g × 26.04 g÷ 1 mol= 1097 kJ/mol

Therefore, the energy of combustion of acetylene in kJ/mol is 1097 kJ/mol.

7 0
4 years ago
Determine the number of atoms in 5.88 moles sodium.
ozzi
1 mole ------------ 6.02x10²³ atoms
5.88 moles ---- ?

atoms = 5.88 * 6.02x10²³ / 1

= 3.539x10²⁴ atoms

hope this helps!
4 0
3 years ago
One way to get more energy out of fuels is to increase _____, the percentage of energy used for work.
Natasha2012 [34]
<span>One way to get more energy out of fuels is to increase _____, the percentage of energy used for work.

</span><span>C.efficiency

Hope this helps :)</span>
4 0
3 years ago
If I contain 1.86g of krypton gas in a container with a volume of 17.5 liters and at a temperature of 190F, what is the pressure
butalik [34]

Answer:

P = 0.0373 atm

Explanation:

Given data:

Mass of krypton = 1.86 g

Volume of krypton = 17.5 L

Temperature of krypton = 190 F

Pressure of krypton = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/ molar mass

Number of moles = 1.86 g/ 83.9 g/mol

Number of moles = 0.022 mol

Formula:

PV = nRT

P = nRT / V

P =  0.022 mol × 0.0821 atm. L. mol⁻¹. K⁻¹ × 360.928 K /  17.5 L

P = 0.652 atm. L /17.5 L

P = 0.0373 atm

7 0
4 years ago
A sample of a compound containing C, O, and silver (Ag) weighed 1.372 g. On analysis, it was found to contain 0.288 g O and 0.97
Sauron [17]

Answer:

The molecular formula for the compound is Ag₂C₂O₄, silver oxalate.

Explanation:

This is an easy excersise, we relate the moles of the elements in the compound with the molar mass of the total compound.

The sample weighs 1.372 g, with 0.288 g of O, 0.974 g of Ag and the rest, C

Therefore, 1.372g - 0.288 g - 0.974g = 0.112 g are C

We convert the mass to moles

0.288 g / 16g/mol = 0.018 moles of O

0.974 g / 107.87 g/mol = 0.00903 moles of Ag

0.112 g / 12 g/mol = 0.00933 moles of C

Now, the use of the molar mass of the compound. Let's prepare some rules of three:

1.372 g of compound contain 0.018 moles of O, 0.00903 moles of Ag and 0.00933 moles of C

Then, 308.8 g of compound (a mol) must contain:

(308.8 . 0.018) / 1.372 = 4 moles of O

(308.8 . 0.00903) / 1.372 = 2 moles of Ag

(308.8 . 0.00933) / 1.372 =  2 moles of C

The molecular formula for the compound is Ag₂C₂O₄, silver oxalate.

3 0
3 years ago
Read 2 more answers
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