Answer:
n = 2 mol
Explanation:
Given data:
Pressure = standard = 1 atm
Temperature = standard = 273.15 K
Volume = 44.8 L
Number of moles = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × 44.8 L = n × 0.0821 atm.L/ mol.K × 273.15 K
44.8 atm.L = n × 22.43 atm.L/ mol
n = 44.8 atm.L / 22.43 atm.L/ mol
n = 2 mol
Answer:
212.996 or 213 approx.
hope it helps.
Molar mass of Al - 27
Molar mass of N - 14
Molar mass of O - 16
so, the molar mass of (No3)3 will be (14+16×3)3 which is equals to 186.
so, Molar mass of Al(No3)3 will be 186+27 = 213.
levels greater than seven are bases
levels on 7 are neutral
levels low than 7 are acids
there are 14 levels, Acids change litmus paper red and Bases change litmus paper blue.
