Question

I need help with these two problems. [9 and 10] FORMULAS GIVEN!!

Answer 1

Question 9:

1. Use Pythagorean Theorem (a²+b²=c²) to solve for missing side of triangle and rectangle. x²+16²=20², or x²+256=400. So, x²=144, and x=12

2. Use formula: 1/2(h)(b1+b2). 1/2 (12) (30+14).

3. Simplify: 1/2 (12) (44)=1/2(528)=264

Area of whole figure is 264 square mm.

Question 10:

Literally same thing but with trigonometry.

1. Use sine to find out length of dotted line: sin(60°)=x/12

2: Simplify: 12*sin(60°)=x. x≈10.4 (rounded to the nearest tenth)

3. Use Pythagorean Theorem to find out last leg of triangle: 10.4²+x²=12²

4: Simplify: 108.16 +x²=144. x²=35.84 ≈ 6

5: Use formula: 1/2(h)(b1+b2). 1/2 (10.4) (30+36)

6: Simplify: 1/2 (10.4) (66) =343.2

7: Area of figure is about 343.2

Remember, this is an approximate answer with rounding, so it might not be what your teacher wants. The best thing to do is do it yourself again.