3 years ago

(asin θ-bcos θ)²=?

1 answer:

6 0

$(a\sin(\theta) - b\cos(\theta))^2\\= a^2\sin^2(\theta) - 2ab\sin(\theta)\cos(\theta) + b^2\cos^2(\theta)\\= a^2\sin^2(\theta) - ab\sin(2\theta) + b^2\cos^2(\theta)$

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A carpenter cuts a board into three pieces of equal length ... smallest board is 1 ft. in length, how long was the original boar

Nadusha1986 [10]

3 feet? maybe. This question was confusing to read.

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3 years ago

Which set of steps shows the solution to the equation 3y = -9?

Lisa [10]

Answer:

see below

Step-by-step explanation:

3y = -9

Divide each side by 3

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4 years ago

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kow [346]

Answer: B. y=9
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3 years ago

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A software designer is mapping the streets for a new racing game. all of the streets are depicted as either perpendicular or par

ElenaW [278]

The equation of the central street PQ is -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

$-7x+3y=-21.5$

Convert it to the general form given below:

$\rm y=mx+c$

$\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x$ or

$\rm y = \frac{7}{3}x-\frac{21.5}{3}$

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For the slope(m') of the PQ line:

$\rm m'=-\frac{1}{m}$ ( because AB and PQ are perpendicular to each other)

$\rm m' = -\frac{3}{7}$

We know the:

$\rm (y-y')=m'(x-x')$

Where (x', y') = (7, 6), we get:

$\rm (y-6)=-\frac{3}{7} (x-7)$

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$\rm -1.5x-3.5y=-31.5$ (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is -1.5x - 3.5y = -31.5

Learn more about the straight line.

brainly.com/question/3493733

6 0

2 years ago

What are the solutions of the system? {y=2x+6y=x2+5x+6 (−3, 0) and (−2, 0) (0, −3) and (6, 0) (−3, 0) and (0, 6) (0, 6) and

SSSSS [86.1K]

<span>(−3, 0) and (0, 6)

Each of these work in both equations</span>

3 0

3 years ago

Read 2 more answers

(asin θ-bcos θ)²=?​​

(asin θ-bcos θ)²=?