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Ede4ka [16]
3 years ago
10

(asin θ-bcos θ)²=?​​

Mathematics
1 answer:
lara31 [8.8K]3 years ago
6 0

(a\sin(\theta) - b\cos(\theta))^2\\= a^2\sin^2(\theta) - 2ab\sin(\theta)\cos(\theta) + b^2\cos^2(\theta)\\= a^2\sin^2(\theta) - ab\sin(2\theta) + b^2\cos^2(\theta)

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