3 years ago

(asin θ-bcos θ)²=?

1 answer:

6 0

$(a\sin(\theta) - b\cos(\theta))^2\\= a^2\sin^2(\theta) - 2ab\sin(\theta)\cos(\theta) + b^2\cos^2(\theta)\\= a^2\sin^2(\theta) - ab\sin(2\theta) + b^2\cos^2(\theta)$

You might be interested in

A roofing job take 6 workers 8 hours to complete. If the number of workers is inversely proportional to the time a job takes to

Wewaii [24]

its a long time before finishing

7 0

3 years ago

At a bake sell, 3/5 of the baked goods are pies. the rest of the baked goods are the plates of cookies. there are 24 plates of c

vovangra [49]

A: 2/5

B: 24x2= 48+12= 60

C: 4

3 0

3 years ago

A rabbit population doubles every 4 weeks.There are currently five rabbits in a restricted area. If t represents the time in wee

sertanlavr [38]

Doubling formula is this:

$P(t)=P(2)^{\frac{t}{d}}$
where P=initial number of rabbits
t=time
d=time it takes to doulbe

ok, so 4 weeks is the doubling time so that is 4*7=28 days

we wawnt time=98
and oroiginal number of rabbits is 5 so
$P(98)=5(2)^{\frac{98}{28}}$
$P(98)=5(2)^{3.5}$
$P(98)=5(2^3)(\sqrt{2})$
$P(98)=5(8)\sqrt{2}$
$P(98)=40\sqrt{2}$
so P(98)≈56.56
we can't have .56 rabbit so round down or up
about 56 or 57 rabbits in 98 days

8 0

3 years ago

One positive number exceeds three times another positive number by 5. The product of the two numbers is 68. Find the number

kati45 [8]

Answer:12

Step-by-step explanation:

Let the numbers be a and b

a-3b=5 ........equation (1)

There product is :

ab=68 ..........equation (2)

From equation (1)

a-3b=5

Make a the subject of the formula

a=5+3b. ........equation (3)

Substitute equation (3) into equation (2)

(5+3b)b=68

3(b^2)+3b-68=0

The product is -204b^2(17 and -12)

(b+17)(b-12)=0

b=-17 or b=12

So the number is 12

6 0

3 years ago

2) A snail moving at 3.6 m/h; convert to mm/s

jolli1 [7]

Answer:

60mm/s

Step-by-step explanation:

Plz give brianliest and push the thanks button

6 0

3 years ago

Read 2 more answers

(asin θ-bcos θ)²=?​​

(asin θ-bcos θ)²=?