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Tems11 [23]
4 years ago
5

en la plaza de un pueblo se quiere colocar una estatua dedicada a un ciudadano. Se desea situarla a igual distancia de la iglesi

a, el ayuntamiento y el colegio. Traza el punto exacto donde se debe colocarse el monumento.
Mathematics
1 answer:
notka56 [123]4 years ago
8 0

Answer:

Step-by-step explanation:

hhh

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If the value of a is positive, the line slopes upwards.
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You need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture. How much
ozzi

Answer:

A. 605 mL of the 35% solution

B. 55 mL of the 95% solution

Step-by-step explanation:

It is given that, you need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture.

Let x and y be the amount of 35% alcohol solution and 95% alcohol solution (in mL) respectively.

So,

Amount equation: x+y=660        ...(1)

Alcohol equation : 0.35x+0.95y=0.40(660)\Rightarrow 0.35x+0.95y=264     ...(2)

On solving (1) and (2), we get

0.35(660-y)+0.95y=264

231-0.35y+0.95y=264

0.6y=264-231

y=\dfrac{33}{0.6}

y=55

Now, substitute y=55 in (1).

x+55=660  

x=660-55  

x=605  

Therefore, we need 605 mL of the 35% solution  and 55 mL of the 95% solution.

4 0
3 years ago
Make 'm' the subject of the formula'k=3m-2
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Answer:

m =  \frac{k + 2}{3}

Step-by-step explanation:

k = 3m - 2 \\ 3m = k + 2 \\ m =  \frac{k + 2}{3}

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25 POINTS AND BRAINLIEST PLEASE HELP ASAP
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M is a midpoint of BC so:

M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)

Length of MA:

MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}

Length of NB:

NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
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