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lianna [129]
3 years ago
13

A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line?

Mathematics
1 answer:
LenKa [72]3 years ago
3 0
We have y - 2 = m(x + 5), where m = (-1 - 2)/(10 + 5) = -3/15 = -1/5;
Then y - 2 = (-1/5)(x + 5);
5y - 10 = (-1)(x + 5);
5y - 10 = -x - 5;
x + 5y - 5 = 0 is the equation of the line.
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Pavel [41]
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It would be
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4 years ago
I need help with the first two
mel-nik [20]
The work and answer provided are correct, the simpler way of doing it is

1)
1/6 page written in 1/12 of a minute
to write a full page, you would need to write 1/6, 6 times
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\frac{1}{6} \time 6 = 1
and
\frac{1}{12} \times 6 = \frac{6}{12} = \frac{1}{2}

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6 0
3 years ago
Find the vertex of this parabola:<br> y = -x2 + 6x - 8
skelet666 [1.2K]

Answer:

4x-8

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y=-x2+6x-8

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4 0
3 years ago
Need help with this question
Lilit [14]

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6 0
3 years ago
A table contains the ordered pairs (3, 42.25) and (5, 50.75). If the relationship in the table is linear, explain how to find th
aniked [119]

Answer:

The initial value is 29.5

Step-by-step explanation:

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept ( also called initial value)

we have the points

(3,42.25) and (5,50.75)

Find the slope m

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{50.75-42.25}{5-3}

m=\frac{8.5}{2}

m=4.25

substitute in the equation

y=4.25x+b

<em>Find the value of b</em>

with the point (3,42.25)  ( or the other given point)

substitute the value of x and the value of y in the equation and solve for b

42.25=4.25(3)+b

42.25=12.75+b

b=42.25-12.75

b=29.5

substitute

The linear equation is

y=4.25x+29.5

The initial value is the y-intercept (value of y when the value of x is equal to zero)

For x=0

y=4.25(0)+29.5

y=29.5

Therefore

The initial value is 29.5

5 0
3 years ago
Read 2 more answers
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