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vredina [299]
3 years ago
13

The lengths of a certain species of fish were found to be normally distributed. The mean length is 73 cm with a standard deviati

on of 8 cm. In a school of 480 of these fish, about how many would be longer than 57 cm?
Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0

Answer:

251

Step-by-step explanation:

Given - Mean length of fish  = μ= 73  cm

SD  σ =8 c m

Number of fish having a length greater than 57 cm out of 480.

Find the value of  z  at  x = 57

z= \frac{x-\mu}{\sigma} = \frac{57-73}{8}\\=\frac{-16}{8} = -2

Area between  z = − 2 and  z =  ∞

= Area between  z = − 1  and  z = 0 +

Area between  z = 0  and  z = ∞

=0.02275+0.5= 0.52275

Therefore number of fish having teeth greater than 57 cm

= 0.52275*480 = 5.2275*48 = 250.92 ≅251

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tankabanditka [31]

Answer:

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Step-by-step explanation:

Let q represent the quantity of 15% dressing used. Then the amount of 5% dressing is (390 -q). The amount of vinegar in the mix is ...

  0.15q + 0.05(390 -q) = 0.08(390)

  0.10q = 31.2 -19.5 = 11.7 . . . . . . subtract 0.05(390) and simplify

  q = 117 . . . . . . . . . . . . . . . . . . multiply by 10

  390-q = 273

The chef should use 273 mL of the first brand (5% vinegar) and 117 mL of the second brand (15% vinegar).

__

<em>Additional comment</em>

You may have noticed that the value of q is (0.08 -0.05)/(0.10 -0.05)×390. The fraction of the mix that is the highest contributor is the ratio of the difference between the mix value and least contributor, divided by the difference between the contributors: (8-5)/(15-5) = 3/10, the fraction that is 15% vinegar. This is the generic solution to mixture problems.

7 0
3 years ago
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horsena [70]
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If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).
svetoff [14.1K]

Given:

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f(3)=f(2)-4

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3 years ago
The cost of 5 story books is Rs 800. How many books can be bought for Rs 1,440?​
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Answer:

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Step-by-step explanation:

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