9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
The answer is 4/1 you just have to divide 7 from both numbers and then you will get 4/1
(20*6)+(12*6)+(18*10)=312 500-312=188 colored pencil's left.
Answer:-5
Step-by-step explanation:
You need to distribute on both sides so u get
9c-15=20-2c
Move variable to left side and change the sign
-9c+2c-15=20
Move constant to right side and change the sign
-9c+2c=20+15
Connect like terms
-7c=35
Divide
C=-5
Answer:
1. +3=5.
2. x = x + 1.
3. x = x + 1.
Step-by-step explanation:
Hope these are good! :) Have a nice day!