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Gelneren [198K]

3 years ago

15

A developer was buying land. He bought 4 acres at $1,863 per acre. He then spilt the land he purchased into 9 lots. How much sho

uld he sell each lot for just to break even

1 answer:

Tpy6a [65]3 years ago

5 0

Answer:

$1862 ÷9=$207(each lot)

$207 ×4=$828

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Answer:

-12x^2 + 11xy - 2y^2

Step-by-step explanation:

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Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

3 years ago

Trevor is making 2/3 of a recipe for chicken noodle soup. He adds ½ cup of chopped celery. The equation 2/3 c = 1/2 can be used

Nikitich [7]

Answer:

Cups of chopped celery in original recipe = $\frac{3}{4}\ cups$

Step-by-step explanation:

Given that:

Trevor is making 2/3 of a recipe

Number of cups of chopped celery used = 1/2 cup

The following equation can be used to find the original number of cups of chopped celery used in recipe.

$\frac{2}{3}c=\frac{1}{2}$

Multiplying both sides by 3/2

$\frac{3}{2}*\frac{2}{3}c=\frac{1}{2}*\frac{3}{2}\\\\c= \frac{3}{4}\\$

Hence,

Cups of chopped celery in original recipe = $\frac{3}{4}\ cups$

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3 years ago

Write this number expanded form 325.809

stira [4]

300+20+5+.800+09 I hope that is what your looking for good luck :)

5 0

3 years ago

Given a sample space, and events A and B, where P(A)= 0.5 and P(B)=0.5. Which of the following values for P(A and B) are not pos

user100 [1]

Option a, option b, option c, option d are not possible values for P(A ∩ B)

Solution:

Given A and B are independent events.

P(A) = 0.5 and P(B) = 0.5

To find which of the following values for P(A and B) are not possible.

P(A and B) = P(A ∩ B)

P(A ∩ B) = P(A) × P(B)

= 0.5 × 0.5

P(A ∩ B) = 0.25

Option a: All are possible.

All answers are not possible for two independent events.

Option b: 0.35

We found that P(A and B) is 0.25.

So, 0.35 is not possible value.

Option c: 0.5

We found that P(A and B) is 0.25.

So, 0.5 is not possible value.

Option d: 0

We found that P(A and B) is 0.25.

So, 0 is not possible value.

Option e: 0.25

We found that P(A and B) is 0.25.

So, 0.25 is the possible value.

Hence, 0.35, 0.5, 0 are not possible values.

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3 years ago